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Free_Kalibri [48]
2 years ago
14

Here is a sequence of numbers:

Mathematics
1 answer:
Anettt [7]2 years ago
8 0

Triangular number sequnce

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Write the first three terms of the sequence defined by the recursive formula if a1=2.
gogolik [260]

The first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2

Given:

an =  \frac{an - 1}{4}  - 2

where,

n = number of terms

First term, a1 = 2

Second term, a2

an =  \frac{an - 1}{4}  - 2

a2 = {(2 - 1)/ 4} - 2

= 1/4 - 2

= (1-8) / 4

= - 7/4

Third term, a3

= {(3-1) / 4} - 2

= 2/4 - 2

= 1/2 - 2

= (1-4) / 2

= -3/2

Therefore, the first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2

Learn more about sequence:

brainly.com/question/6561461

4 0
2 years ago
1. Write an addition equation, a subtraction equation, and a multiplication equation that has -2 as a solution. Solve each equat
Sphinxa [80]
5 + -7 = -2
5 - 7 = -2
-1 x 2 = -2
7 0
2 years ago
Please help thank you ​
Eduardwww [97]

Answer:

its (C) or (B) but my answer would be (B)

Step-by-step explanation:

3 0
3 years ago
11. Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x) 5 5 0 x , 0
NISA [10]

Question not properly presented

Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x)

0 ------ x<0

x²/25 ---- 0 ≤ x ≤ 5

1 ----- 5 ≤ x

Use the cdf to obtain the following.

(a) Calculate P(X ≤ 4).

(b) Calculate P(3.5 ≤ X ≤ 4).

(c) Calculate P(X > 4.5)

(d) What is the median checkout duration, μ?

e. Obtain the density function f (x).

f. Calculate E(X).

Answer:

a. P(X ≤ 4) = 16/25

b. P(3.5 ≤ X ≤ 4) = 3.75/25

c. P(4.5 ≤ X ≤ 5) = 4.75/25

d. μ = 3.5

e. f(x) = 2x/25 for 0≤x≤2/5

f. E(x) = 16/9375

Step-by-step explanation:

a. Calculate P(X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(X ≤ 4) = F(x) {0,4}

P(X ≤ 4) = x²/25 {0,4}

P(X ≤ 4) = 4²/25

P(X ≤ 4) = 16/25

b. Calculate P(3.5 ≤ X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(3.5 ≤ X ≤ 4) = F(x) {3.5,4}

P(3.5 ≤ X ≤ 4) = x²/25 {3.5,4}

P(3.5 ≤ X ≤ 4) = 4²/25 - 3.5²/25

P(3.5 ≤ X ≤ 4) = 16/25 - 12.25/25

P(3.5 ≤ X ≤ 4) = 3.75/25

(c) Calculate P(X > 4.5).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(4.5 ≤ X ≤ 5) = F(x) {4.5,5}

P(4.5 ≤ X ≤ 5) = x²/25 {4.5,5}

P(4.5 ≤ X ≤ 5)) = 5²/25 - 4.5²/25

P(4.5 ≤ X ≤ 5) = 25/25 - 20.25/25

P(4.5 ≤ X ≤ 5) = 4.75/25

(d) What is the median checkout duration, μ?

Median is calculated as follows;

∫f(x) dx {-∝,μ} = ½

This implies

F(x) {-∝,μ} = ½

where F(x) = x²/25 for 0 ≤ x ≤ 5

F(x) {-∝,μ} = ½ becomes

x²/25 {0,μ} = ½

μ² = ½ * 25

μ² = 12.5

μ = √12.5

μ = 3.5

e. Calculating density function f (x).

If F(x) = ∫f(x) dx

Then f(x) = d/dx (F(x))

where F(x) = x²/25 for 0 ≤ x ≤ 5

f(x) = d/dx(x²/25)

f(x) = 2x/25

When

F(x) = 0, f(x) = 2(0)/25 = 0

When

F(x) = 5, f(x) = 2(5)/25 = 2/5

f(x) = 2x/25 for 0≤x≤2/5

f. Calculating E(X).

E(x) = ∫xf(x) dx, 0,2/5

E(x) = ∫x * 2x/25 dx, 0,2/5

E(x) = 2∫x ²/25 dx, 0,2/5

E(x) = 2x³/75 , 0,2/5

E(x) = 2(2/5)³/75

E(x) = 16/9375

4 0
2 years ago
Expand and simplify: (x-5)(x+5)
stealth61 [152]
X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)





5 0
3 years ago
Read 2 more answers
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