Answer:
0, ±1, ±7,±1/3, and ±7/3
Step-by-step explanation:
In the function:
3x^5 - 2x² + 7x
x can be extracted as the greatest common factor, as follows:
x(3x^4 - 2x + 7)
then, zero is one root of the function.
According to Rational Root Theorem:
possible rational roots = factors of the constant/factors of the leading coefficient
For this case, factors of the constant (7) are: ±1 and ±7
For this case, factors of the leading coefficient (3) are: ±1 and ±3
Then:
possible rational roots = ±1/±1, ±7/±1, ±1/±3 and ±7/±3. Simplifying: ±1, ±7,±1/3, and ±7/3
Step-by-step explanation:
if x-4 is a factor of 2x^3 + x^2- 26x - 40
then f(4) = 0
f(x) = 2x^3 + x^2- 26x - 40
f(4) = 2(4)^3 + (4)^2 - 26(4) - 40
f(4)= 2(64) + 16 - 104 - 40
f(4) = 128 + 16 - 104 - 40
f(4) = 0
hence factorize completely is the photo
Try this solution, note, checking was not performed.
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4
