Answer:
Draw a 3-D of a terrain indicating different fault behaviors. Use the terrain below. Be sure that the entire terrain should cover at least three type of fault. Labcl the fault arcas and its part
Volume=(pi)(radius^2)(height)
Volume=(pi)(5^2)(12)
V=(pi)(25)(12)
V=(pi)(300)
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer:
What is it you need help with?
Step-by-step explanation:
Which one
Answer:
Step-by-step explanation:
3x+y+z= 4
3x+ y = 4 - z
y = 4-z-3x
We then make parallel
y-2 = 4−z−3x
y-2 = 4-2 -z-3x
y-2 = 2-z-3x
y = -z-3x+2
