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Llana [10]
3 years ago
7

$66.25 divided among 4 people

Mathematics
1 answer:
Serjik [45]3 years ago
7 0
The actual answer would be $16.5625 but you can just say $16.5
You might be interested in
Find all real values of $v$ that satisfy the equation $(v+6)^2 = 324$. If you find more than one, then list your values in incre
Karolina [17]
We have that

(v+6)^2 = 324-----> I raise to 1/2 both members----> [(v+6)^2]^(1/2)=(324)^(1/2)[(v+6)]=(324)^(1/2)-------------> v+6=√324
v=√324-6---------> 18-6=12
v=12

the answer is v=12
8 0
3 years ago
Read 2 more answers
Is this right ? Geometry
elixir [45]
No, 12 is the wrong answer. 5 is correct

This is because since a and c are congruent that means y=52. And we already know that every triangle adds up to 180 degrees so, you add A and C and get 104 (52+52).
And 180-104=76 so, 14x+6 must =76.
14(5)=70+6=76. 76+104=180, therefore, x=5.
7 0
3 years ago
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A square field has an area of 144 metres squared. If Andrea walked 10 times around this field, what distance did she cover?
Novosadov [1.4K]

Answer:

480m

Step-by-step explanation:

First we have to find the perimeter of the field.

We know that the area is 144m and that the field is a square.

Since a squares sides are all equal, we can do \sqrt{144}, which is 12m.

So, one side of the field is 12m; now we just find the perimeter which is easy since its a square. 12*4=48m

If Andrea walked around it 10 times, then we just multiply the perimeter by 10

48*10=480m

7 0
3 years ago
Please help <br> 8x + 6 = 34<br> solve for x
alexgriva [62]

Answer:         for the first one x>-6, for the second one x< or equal to 5

Step-by-step explanation:

6 0
3 years ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
Read 2 more answers
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