Answer:
Explanation:
To simplify a polynomial, we have to do two things: 1) combine like terms, and 2) rearrange the terms so that they're written in descending order of exponent.
First, we combine like terms, which requires us to identify the terms that can be added or subtracted from each other. Like terms always have the same variable (with the same exponent) attached to them. For example, you can add 1 "x-squared" to 2 "x-squareds" and get 3 "x-squareds", but 1 "x-squared" plus an "x" can't be combined because they're not like terms.
Let's identify some like terms below.
f(x)=−4x+3x2−7+9x−12x2−5x4
Here you can see that -4x and 9x are like terms. When we combine (add) -4x and 9x, we get 5x. So let's write 5x instead:
f(x)=5x+3x2−7−12x2−5x4
Let's do the same thing with the x-squared terms:
f(x)=5x+3x2−7−12x2−5x4
f(x)=5x−9x2−7−5x4
Now there are no like terms left. Our last step is to organize the terms so that x is written in descending power:
f(x)=−5x4−9x2+5x−7
Step-by-step explanation:
The equation representing the cost of the ride is R = $5 + $0.45dd.
<h3>What is flat fee? </h3>
The flat fee charged is the fixed cost. This cost remains constant regardless of the distance travelled. The additional fee is the variable cost. It increases with the distance travelled.
<h3> Derivation of the equation that represents cost of the ride.</h3>
Total cost = fixed cost + (variable cost x miles driven)
R = $5 + $0.45dd
To learn more about flat fees, please check: brainly.com/question/25879561
The grade of the path in the mountain is calculated by determining first the ratio between the rise over the run and multiplying the ratio by 100%.
For Path A:
grade = (rise / run) x 100%
grade = (1414/ 3535) x 100% = 40%
<em>Answer: 40%</em>
For Path B:
grade = (rise / run) x 100%
grade = (4.26 m/ 22 m) x 100% = 19.36%
Answer: 19.36%
Answer:
The minimum sample size needed for use of the normal approximation is 50.
Step-by-step explanation:
Suitability of the normal distribution:
In a binomial distribution with parameters n and p, the normal approximation is suitable is:
np >= 5
n(1-p) >= 5
In this question, we have that:
p = 0.9
Since p > 0.5, it means that np > n(1-p). So we have that:
The minimum sample size needed for use of the normal approximation is 50.
