The surface area of the figure given is of: 61.3 yd².
<h3>What is the combined surface area of a figure?</h3>
The combined surface area of a figure is the area of each figure.
This figure is composed by:
- A triangle with base 6 yd and one leg 11.4 yd.
The area of the circle is given as follows:
For the triangle, we need to find it's height, which is the <u>leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4</u>, hence:
h² + 3² = 11.4²
h = 11 yd.
Hence the area of the triangle is:
A = 0.5 x 6 x 11 = 33 yd²
The surface area of the figure is:
9pi + 33 yd² = 61.3 yd².
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The total length of the segment AC is the sum of AB and CB, which gives, CB = 9
<h3>How can the length of CB be found?</h3>
The given parameters are;
- AC = 17
- AB = 32 + 3•x
- CB = 57 + 6•x
Required: <em>CB</em>
Solution:
AC = <em>AB + CB</em> by segment addition property
Therefore;
AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x
17 = 89 + 9•x
CB = 57 + 6•x = 57 + 6 × (-8) = 9
Therefore;
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Answer:
3, 10
Step-by-step explanation:
1.
5x-1=14 ->
5x=15 ->
x=3.
2.
15+3x=45 ->
3x=45-15=30 ->
3x=30 ->
x=10.
Hope that help! :)
Answer:
10 cm
Step-by-step explanation:
From the diagram,
Applying,
lw = 5/2(bh)..................... Equation 1
Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.
make w the subject of the equation
w = 5(bh)/2l............... Equation 2
From the diagram,
Given: l = 12 cm, b = 6 cm, h = 8 cm
Substitute into equation 2
w = 5(6×8)/(2×12)
w = 10 cm
Hence the width of the rectangle is 10 cm
Answer:
m=2
Step-by-step explanation:
math is hard
