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Ronch [10]
3 years ago
5

Explain why a) Kl (potassium iodide) dissolves in water, but b) it will not dissolve in hexane.

Chemistry
2 answers:
salantis [7]3 years ago
8 0

Answer:It forms single phase mixtures (solutions) with other polar and ionic substances. ... Since water is less dense than this non-polar mixture, the bubbles rise to the top. Potassium iodide, an ionic compound, dissolves easily in water but does not dissolve in chloroform and hexane.

Explanation:

Blababa [14]3 years ago
6 0

Answer:

Explanation: Brief description of demonstration

Three clear liquids form three distinct layers in a cylinder. Iodine crystals sprinkled on the top layer sink and form pink solutions with the top and bottom layers but do not dissolve in the middle. When the liquids are mixed, two layers form: a pink layer on the bottom, and a colorless layer on top. When white potassium iodide crystals are added and the liquids are mixed again, the colorless layer turns yellow.

Concepts illustrated:

• Phases and phase boundaries (surfaces)

• Density

• Polar/non-polar (hydrophilic/hydrophobic) interactions

• Solubility, miscibility

• Chemical reaction

• Extraction

• [Solution and emulsion]

Materials

• Clear glass reaction cylinder or gas-washing bottle, at least 200 mm tall, with ground glass stopper (A cylindrical container is preferable to a separatory funnel for this experiment. The stopper must be non- reactive, and, to prevent a potentially dangerous pressure build-up, the stopper must be easily released. For a very small class, a large test tube with a suitable stopper is adequate. )

• Equal volumes of chloroform, water, and hexane (The volume of each liquid should be a little more than one-fourth the volume of the cylinder.)

• Iodine crystals and small spatula

• Potassium iodide crystals and medium spatula

Preparation

Work in a hood. Pour the chloroform into the reaction cylinder. Add the water and allow the liquids to separate completely. (If necessary, speed the process by holding the cylinder vertical and gently swirling the solution with a circular motion.) Tip the cylinder and pour the hexane slowly down the side to prevent mixing. Close the cylinder and set it aside, away from sources of heat, until time for the demonstration.

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Name each of the following molecular binary compounds:
Tanya [424]

Answer:

Explanation:

From the given information; we are to assign the correct naming for the molecular binary compounds.

01. CaCl2 → Calcium CHloride

02. HI (g) → Hydrogen mono iodide gas

03. HI (aq) →  Hydroiodic acid

04. BH3 → Borontrihydride

05. Cl2O6 → Dichlorine hexoxide

06. ClF → Chlorine monoflouride

07. P2Cl4 → Phosphorus tetrachloride

08. I2O5 → Diiodine pentaoxide

09. BrF5 → Bromine pentaflouride

10. HBr(aq) → Hydrobromic acid

11. IF7 → Iodine heptaflouride

12. NF3 → nitrogen triflouride

13. H2Se(aq) → hydroselenic acid

14. BrCl → Bromine monochloride

15. H2Se(g) → Hydrogen Selenide

16. SnO2 → Tindeoxide

17. HBr(g) →  Hydrogenbromide gas

18. AsF3 → Arsenic triflouride

19. N2O3 → Dinitrogentrioxide

20. IF4 → Iodine pentafluoride

01. hydroiodic acid  → HI (aq)

02. hydrogen monoiodide gas → HI (g)

03. diiodine tetraoxide → I2O4

04. bromine monofluoride → BrF

05. silicon tetrahydride  → SiH4

06.  tetraphosphorus hexaoxide → P4O6

07. disulfur monoxide → S2O

08. carbon monooxide → CO

09. hydrogen monochloride gas → Hcl

10. tetraphosphorus decaoxide → P4O10

11. dibromine monoxide → Br2O

12. dinitrogen tetrafluoride → N2F4

13. disilicon hexahydride → SiH6

14. tetraarsenic hexaoxide → As4O6

15. hydrochloric acid → HCl (aq)

16.  arsenic trihydride → AsH3

17. iodine heptafluoride → IF7

18. bromine dioxide → BrO2

19. disulfur decafluoride → S2F10

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Write a balanced equation for the reaction between aqueous strontium chloride and aqueous lithium phosphate to form solid stront
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First, let's write the chemical formula for each of the substances mentioned in the problem.

Strontium Chloride: SrCl₂
Lithium Phosphate: Li₃PO₄
Strontium Phosphate: Sr₃(PO₄)₂
Lithium Chloride: LiCl

So, the balanced chemical reaction is:

<em>3 SrCl₂ (aq) + 2 Li₃PO₄ (aq) ---> Sr₃(PO₄)₂ (s) + 6 LiCl (aq)</em>

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<h3>Explanation</h3>

ΔE = h · f

Where

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However, only λ is given.

f = c / λ

Where

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f = 2.998 × 10⁸ / 2.21 = 1.36 × 10⁸ s⁻¹.

ΔE = h · f = 6.626 × 10⁻³⁴ × 1.36 × 10⁸ = 9.01 × 10⁻²⁶ J

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