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Ronch [10]
3 years ago
5

Explain why a) Kl (potassium iodide) dissolves in water, but b) it will not dissolve in hexane.

Chemistry
2 answers:
salantis [7]3 years ago
8 0

Answer:It forms single phase mixtures (solutions) with other polar and ionic substances. ... Since water is less dense than this non-polar mixture, the bubbles rise to the top. Potassium iodide, an ionic compound, dissolves easily in water but does not dissolve in chloroform and hexane.

Explanation:

Blababa [14]3 years ago
6 0

Answer:

Explanation: Brief description of demonstration

Three clear liquids form three distinct layers in a cylinder. Iodine crystals sprinkled on the top layer sink and form pink solutions with the top and bottom layers but do not dissolve in the middle. When the liquids are mixed, two layers form: a pink layer on the bottom, and a colorless layer on top. When white potassium iodide crystals are added and the liquids are mixed again, the colorless layer turns yellow.

Concepts illustrated:

• Phases and phase boundaries (surfaces)

• Density

• Polar/non-polar (hydrophilic/hydrophobic) interactions

• Solubility, miscibility

• Chemical reaction

• Extraction

• [Solution and emulsion]

Materials

• Clear glass reaction cylinder or gas-washing bottle, at least 200 mm tall, with ground glass stopper (A cylindrical container is preferable to a separatory funnel for this experiment. The stopper must be non- reactive, and, to prevent a potentially dangerous pressure build-up, the stopper must be easily released. For a very small class, a large test tube with a suitable stopper is adequate. )

• Equal volumes of chloroform, water, and hexane (The volume of each liquid should be a little more than one-fourth the volume of the cylinder.)

• Iodine crystals and small spatula

• Potassium iodide crystals and medium spatula

Preparation

Work in a hood. Pour the chloroform into the reaction cylinder. Add the water and allow the liquids to separate completely. (If necessary, speed the process by holding the cylinder vertical and gently swirling the solution with a circular motion.) Tip the cylinder and pour the hexane slowly down the side to prevent mixing. Close the cylinder and set it aside, away from sources of heat, until time for the demonstration.

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Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor
irina [24]

Answer:

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Explanation:

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5 0
4 years ago
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius​
lukranit [14]

Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

  • Answer: <u>5.5g</u>

Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

5 0
3 years ago
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