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kotykmax [81]
4 years ago
9

Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor

rections. Species added Total concentration (solution a) HCl 10-3 M (solution b) NaCl 10-3 g.
Chemistry
1 answer:
irina [24]4 years ago
5 0

Answer:

HCl solution - H30+ and Cl ions. pH 3

NaCl - Na+ and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = -log [H+] = -log(10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na+ and Cl- ions. None of these ions affect pH

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Based on your answer in part B, arrange the five elements in order of their reactivity. Drag the most reactive element to the to
amm1812

Answer: Order of the elements from most reactive to least reactive is:

Mg >  Zn > Fe > H > Cu

Explanation: Reactivity of the elements is the tendency of the elements to loose or gain electrons with ease.

As, all the given elements are metals, so the metals which will loose electrons easily will be more reactive. To study the reactivity of metals, we use reactivity series.

The metals which are more reactive are placed on the top of the reactivity series and which are less reactive are placed at the bottom.

Hence, the order of the elements from most reactive to least reactive is:

Mg >  Zn > Fe > H > Cu

Reactivity series is attached below.

6 0
4 years ago
5. Forces (or actions) always come in pairs. They<br> are____and_____
azamat

Answer:

equal and opposite

Explanation:

The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object

3 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
PLS HELP
kipiarov [429]

Answer:

Change in plate tectonic leads to change in earth surfaces.

Plate tectonics have changed Earth’s surface over time because the earth surface is placed on these plate tectonics. Earth's outer surface is divided into various plates that slowly move over the mantle which changes Earth's surface over time by merging and separating of landmasses that turn into continents.

The movement of tectonic plates is responsible for the creation of landforms such as volcanoes and ridges. Some volcanoes are formed when the tectonic plates pull apart from one another whereas some volcanoes are produced when a tectonic plate slides over one another so we can conclude that change in plate tectonic leads to change in earth land forms.

Explanation:

3 0
3 years ago
How many kilojoules of heat are absorbed when 2.00 L of water is heated from 19*C to 80*C? (Show all work including the equation
Snowcat [4.5K]

Answer:

The answer to your question is 510.7 kJ

Explanation:

Data

Q = ?

Volume = 2 L

Temperature 1 = T1 = 19°C

Temperature 2 = T2 = 80°C

Specific heat = 4.186 J/kg°C

Density of water = 1 g/ml

Equation

              Q = mC(T2 - T1)

Process

1.- Calculate the mass of water

mass = density x volume

mass = 1 x 2000

mass = 2000 g

2.- Substitute values in the Heat formula

              Q = (2000)(4.186)(80 - 19)

-Simplification

               Q = (2000)(4.186)(61)

-Result

              Q = 510692 J  or 510.7 kJ

7 0
4 years ago
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