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kotykmax [81]
3 years ago
9

Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor

rections. Species added Total concentration (solution a) HCl 10-3 M (solution b) NaCl 10-3 g.
Chemistry
1 answer:
irina [24]3 years ago
5 0

Answer:

HCl solution - H30+ and Cl ions. pH 3

NaCl - Na+ and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = -log [H+] = -log(10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na+ and Cl- ions. None of these ions affect pH

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URGENT!!!!!!
Marrrta [24]

Answer:

(a) 0.0301g

Explanation:

4 0
3 years ago
PH & POH
Mashcka [7]

Answer:

<h2>4.0 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H}^{+}]

From the question we have

ph =  -  log(9.25 \times  {10}^{ - 5} )  \\  = 4.03385

We have the final answer as

<h3>4.0</h3>

Hope this helps you

5 0
3 years ago
When many atoms are split in a chain reaction, a large explosion occurs. This is an example of what type of energy conversion? (
lara31 [8.8K]

Answer:

I think is chemical and nuclear

8 0
3 years ago
Read 2 more answers
20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc
bezimeni [28]

Answer:

Concentration of the barium ions  = [Ba^{2+}] = 0.4654 M

Concentration of the chloride ions  = [Cl^{-}]=0.9308 M

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride  = 0.1355 M

n=0.1355 M\times  0.04389 L=0.005947 mol

Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

\frac{1}{2}\times 0.05947 mol=0.029735 mol barium hydroxide

Moles of barium hydroxide = 0.029735 mol

Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

=1\times 0.029735 mol= 0.029735 mol

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL  = 63.89 mL = 0.06389 L

Concentration of the barium ions =[Ba^{2+}]

[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M

Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M

8 0
3 years ago
Which is the formula for diarsenic pentoxide?
Olenka [21]
Formula for diarsenic pentoxide
As2O5
7 0
3 years ago
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