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kotykmax [81]
3 years ago
9

Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor

rections. Species added Total concentration (solution a) HCl 10-3 M (solution b) NaCl 10-3 g.
Chemistry
1 answer:
irina [24]3 years ago
5 0

Answer:

HCl solution - H30+ and Cl ions. pH 3

NaCl - Na+ and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = -log [H+] = -log(10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na+ and Cl- ions. None of these ions affect pH

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Answer:

Ag+

Explanation:

anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)

8 0
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2NO(g) N2(g) + O2(g); Keq = 2.1 × 1030 What does the value of the equilibrium constant indicate?
olga_2 [115]
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
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A thermos bottle uses a ______ to keep heat in the thermos
attashe74 [19]

Answer:

a thermos bottle uses a vacuum to keep heat in the thermos.

4 0
2 years ago
The osmolarity of a 1-l bottle of 5% dextrose solution is _____ mosm/l.
Pachacha [2.7K]
M(dextrose) = 50 g.
V(solution) = 1 L.
n(dextrose) = 50 g ÷ 180 g/mol.
n(dextrose) = 0,27 mol.
Osmotic concentration (osmolarity)<span> is a measure of how many </span><span>osmoles of particles of solute</span><span> it contains </span>per liter.
The osmolarity = n(dextrose) ÷ V(solution).
The osmolarity = 0,27 mol ÷ 1 L.
The osmolarity = 0,27 mol/L · 1000 mmol/m.
The osmolarity (dextrose) = 270 mosm/L.
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7 0
3 years ago
Read 2 more answers
A mixture is made by combining 1.49 lb of salt and 3.82 lb of water.
Pavel [41]

Answer:

28%

Explanation:

concentration=(solute mass/solution mass)*100

C=concentration

md-solute mass

ms-solution mass

the solution mass is equal to the sum of the solute and solvent mass

ms=3.82+1.49=5.31lb

c=1.49/5.31 * 100=0.28*100=28%

7 0
3 years ago
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