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shtirl [24]
3 years ago
7

6cos(20πt-π)+6√3cos(20πt-π\2)

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

Step-by-step explanation:

{ \tt{ = (6 \cos(20\pi t)  \cos(\pi)  +  6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t)  \cos( \frac{\pi}{2} )  +  \sin(20\pi t)   \sin( \frac{\pi}{2} )) }} \\  = { \tt{ (- 6t + 0) + (0 + 0)}} \\  = { \tt{ - 6t}}

Note that π is 180°

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Plzzz help me asap plzzz someone <br> the question is on the picture
Roman55 [17]

Answer:

(3 , 2.5)

Step-by-step explanation:

.5x + y = 4

y = .5x+1


.5x + (.5x + 1) = 4

x + 1 = 4

x = 3


y = .5(3)+1

y = 1.5 + 1

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7 0
3 years ago
What is the vertex of the following function? f(x) = 2(x+8)^2 - 2
netineya [11]

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4 0
2 years ago
Jaylo bought a television priced at $349. She received a 20% discount and paid a 7% sales tax. What is the total price of the te
maw [93]

Answer:

B

Step-by-step explanation:

349 ---100%

x ------ 20%

x= (349×20)÷100

x=69.8

349-69.8=279.2

279.2 ---100%

x-----7%

x=(279.2×7)÷100

x=19.54

Final result

279.2+19.54=298.74

And final result is B

8 0
3 years ago
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Anika [276]

The correct answer is A). None

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It is necessary to note that one of the roots is a complex number and root of complex number always in pair of the conjugate to each other.

Since x=6+i

Conjugate of (6+i) is (6-i)

<em>Therefore, (6-i) is 3rd required root of a polynomial </em>

<em>The correct answer is A). None</em>

4 0
4 years ago
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