Answer:
Solution: x = 2, y = -1 or (2, -1)
Step-by-step explanation:
Equation 1: 2x + y = 3
Equation 2: 5x - 2y = 12
Using the substitution method:
Transform the Equation 1 into its slope-intercept form:
2x + y = 3
2x - 2x + y = -2x + 3
y = 2x + 3
Substitute the value of y = -2x + 3 into Equation 2:
5x - 2y = 12
5x - 2(-2x + 3) = 12
5x + 4x - 6 = 12
9x - 6 = 12
9x - 6 + 6 = 12 + 6
9x = 18
9x/9 = 18/9
x = 2
Substitute the value of x = 2 into Equation 2 to solve for y:
5x - 2y = 12
5(2) - 2y = 12
10 - 2y = 12
10 - 10 - 2y = 12 - 10
-2y = 2
-2y/-2 = 2/-2
y = -1
Double-check whether the values for x and y will provide a true statement for both equations:
Equation 1: 2x + y = 3
2(2) + (-1) = 3
4 - 1 = 3
3 = 3 (True statement)
Equation 2: 5x - 2y = 12
5(2) - 2(-1) = 12
10 + 2 = 12
12 = 12 (True statement)
Therefore, the correct answers are: x = 2; y = -1 or (2, -1).
Answer:
find the difference. find the sum
Step-by-step explanation:
Answer:
the answer is linear
Step-by-step explanation:
Linear is a line while non linear is not.
The area of the polygon with vertices W (1, 1), X (4, 4), Y (7, 1), and S (4, −8) is 36.
Have a great day! :D
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
