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Genrish500 [490]
3 years ago
13

Which is the lowest energy level having “d” orbitals?

Chemistry
1 answer:
lora16 [44]3 years ago
8 0

Answer:

n=3 the minimum n for which d orbital exist.

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If 100 ml of a 0.5 M HCI Solution is diluted with water to 1000ml, what is the new concetration?
Vesna [10]

Answer:

0.05\ \text{M HCl}

Explanation:

V_1 = Initial volume = 100 mL

V_2 = Final volume = 1000 mL

M_1 = Initial concentration = 0.5 M

M_2 = Final concentration

We have the relation

\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}\\\Rightarrow M_2=M_1\dfrac{V_1}{V_2}\\\Rightarrow M_2=0.5\times \dfrac{100}{1000}\\\Rightarrow M_2=0.05\ \text{M HCl}

The new concentration is 0.05\ \text{M HCl}.

3 0
3 years ago
What is a jet stream?
trasher [3.6K]
<span>a narrow, variable band of very strong, predominantly westerly air currents encircling the globe several miles above the earth. There are typically two or three jet streams in each of the northern and southern hemispheres.</span>
5 0
3 years ago
A solution of acetic acid, CH3CO₂H(aq), is at equilibrium. How would the
s344n2d4d5 [400]

If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation. (Option C)

<h3>How do systems at equilibrium respond to perturbation?</h3>

When a system at equilibrium suffers a perturbation, it shifts its equilibrium position to counteract such perturbation.

Let's consider a solution of acetic acid at equilibrium.

CH₃CO₂H(aq) = CH₃CO₂⁻(aq) + H⁺(aq)

If more acetic acid were added to the solution, the system will shift toward the products to counteract such an increase.

How would the system change if more acetic acid were added to the solution?

A. [H⁺] would decrease and [CH₃CO₂⁻] would increase. NO.

B. [H⁺] and [CH₃CO₂⁻] would decrease. NO.

C. [H⁺] and [CH₃CO₂⁻] would increase. YES. Both products would increase.

D. [H⁺] would increase and [CH₃CO₂⁻] would decrease. NO.

If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation.

Learn more about equilibrium here: brainly.com/question/2943338

#SPJ1

3 0
2 years ago
(reply with the answer or get reported) Please help and thanks​
alexgriva [62]
1. C) 10
2. C) 2.33 mole
7 0
3 years ago
What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?
dezoksy [38]
Hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

D = 5.02 g/cm³
4 0
4 years ago
Read 2 more answers
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