Balanced equation:
Pb(SO₄)₂ + 2 Zn → 2 ZnSO₄ + Pb
From the equation we found that 2 moles of Zn form 2 moles of ZnSO₄
so 0.582 mole of Zn will produce 0.582 ZnSO₄
Molar mass of ZnSO₄ = 161.47 g/mole
Mass of ZnSO₄ formed = 161.47 x 0.582 = 94.0 grams
Answer:
Valence electrons. they can be used to determine the group of an element.
Explanation:
Answer:
20 ounces of 14% solution and 8 ounces of 7% solution.
Explanation:
Let the amount of 14% solution required be A and the amount of 7% solution required be B.
Mixture of A and B must give 28 ounces:
A + B = 28 ................. Eqn 1
Also, mixture of 14% A and 7% B must give 12%, 28 ounces solution:
0.14A + 0.07B = 0.12(28) = 3.36...................Eqn 2
From eqn 1, B = 28 - A, eqn 2 becomes:
0.14A + 0.07(28 - A) = 3.36
0.07A = 3.36 - 1.96
A = 20 ounces
Substitute the value of A into eqn 1 to get B:
20 + B = 28
B = 8 ounces.
Hence, 20 ounces of 14% hydrochloric acid and 8 ounces of 7% hydrochoric acid should be mixed together in order to get 28 ounces of 12% solution.
Answer:
P = 0.0373 atm
Explanation:
Given data:
Mass of krypton = 1.86 g
Volume of krypton = 17.5 L
Temperature of krypton = 190 F
Pressure of krypton = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 1.86 g/ 83.9 g/mol
Number of moles = 0.022 mol
Formula:
PV = nRT
P = nRT / V
P = 0.022 mol × 0.0821 atm. L. mol⁻¹. K⁻¹ × 360.928 K / 17.5 L
P = 0.652 atm. L /17.5 L
P = 0.0373 atm
Order of Solubility of given alcohols is as follow,
Ethanol Butanol Hexanol
Highly Soluble ---------->--------------------->------------------------>---Slightly Soluble
As we know Like dissolves Like. Water is a polar solvent and dissolves readily those compounds which are polar in nature. The solubility of all these alcohols is due o the -OH (hydroxyl) group which tends to form Hydrogen Bond interactions with the water molecules. The difference comes in the alkyl group of these compounds. The akyl group is non polar in nature and immiscible in water. As the non polar chain increases from ethanol to hexanol, so the solubility also decreases from ethanol to hexanol.
