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2 years ago

Which expression is equivalent to 3(m − 3) + 4?

Mathematics

1 answer:

Elanso [62]2 years ago

4 0

Answer:

3m − 5

Step-by-step explanation:

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Given that Cos0=5/13,find a)Tan0,b)Sin0,c)Sec0,d)Co sec0,e)Cot0,

aliina [53]

Step-by-step explanation:

cos 0=5/13. B/H

p=√h2 - b2

= √13 square -5 square

=√169 -25

=√144

=12 Ans

Tan0=p/b =12/5. , sin0=p/h =12/13,. sec0= h/b =13/5 ,. Co sec0 =h/p =13/12 , cot0 =b/p=5/12

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4 0

2 years ago

Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$

Exercise 2:

You simply have to compute the trigonometric function:

$\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$

So, we have

$z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i$

7 0

2 years ago

12. For angle A it is known that sin(A)>0 and tan (A) <0. If A is drawn in standard position, in which quadrant

Dafna11 [192]

Answer:

Quadrant 2

Step-by-step explanation:

Sin = opp/hyp and opp is positive in quadrants 1 & 2.

Tan = opp/adj - we need one of these values to be positive and the other negative. adj is negative in quadrants 2 & 3.

Quadrant 2 is found in both of the scenarios that we need to occur.

8 0

3 years ago

Please help. i not smart

____ [38]

Answer:

It is hard to see the numbers.

But I am pretty sure it is 6x+6.

Step-by-step explanation:

Hope this helps! :D

4 0

2 years ago

A guy wire 30 ft long supports an antenna at a point that is 24 ft above the base of the antenna.

GalinKa [24]

Use Pythagorean Theorem
c2 = a2 + b2
152 = a2 + 12
a2 = 152 - 122
=225 - 144 = 81
a = 9 ft
Distance from base of antenna = 9ft

4 0

2 years ago