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Alex73 [517]
3 years ago
11

PLEASE HELP! WILL GIVE BRAINLIEST!

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

Answer: the equivalent form of 6(2x+3x+10) are 12x+18x + 60 and 30x+60.

Hope this helps

Dafna11 [192]3 years ago
8 0

Answer:

The equivalent form of 6(2x+3x+10) is 12x+18x + 60 and 30x+60.

Explanation:

12x+18x + 60 is one of the equivalent form of 6(2x+3x+10) To get another equivalent form we combine like terms.

30x + 60 is the equivalent form of 6(2x+3x+10)

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A student received an 82$ on an exam if there were 50 questions on the exam which ratio would show the number of questions answe
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He answered 41 questions right.

41:50
7 0
3 years ago
Find x in the following triangle pls solve it fast!! Correct answer will get brainliest!!!!
neonofarm [45]

Answer:

c=26

Step-by-step explanation:

So you would use the formula a^2+b^2=c^2

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4 0
3 years ago
Question 4
Ilia_Sergeevich [38]

Answer:

2

Step-by-step explanation:

Given

See attachment for chart

Required

Number of off days

To do this, we simply calculate the expected value of the chart.

This is calculated as:

E(x) = \sum x * f

Where

x = days

f = chances

So, we have:

E(x) = 0* 0.3 + 1 *0.2 + 2 * 0.25 + 3  * 0.2 + 4  * 0.02 + 5 * 0.01 + 6 * 0.01 + 7 * 0.01

E(x) = 1.56

E(x) \approx 2

3 0
2 years ago
What is the solution of 5 = t/2 -3?
Sladkaya [172]

Answer:

t=16

Step-by-step explanation:

you have to change the numbers to get just the variable.

we start from -3.

5=t/2-3

8=t/2

(we multiply by 2 instead of dividing)

8×2=16

t=16

5 0
3 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
insens350 [35]
1) We have that there are in total 6 outcomes If we name the chips by 1a, 1b, 3 ,5 the combinations are: 1a,3 \ 1b, 3 \1a, 5\ 1b, 5\ 3,5\1a,1b. Of those outcomes, only one give Miguel a profit, 1-1. THen he gets 2 dollars and in the other cases he lose 1 dollar. Thus, there is a 1/6 probability that he gets 2$ and a 5/6 probability that he loses 1$.
2) We can calculate the expected value of the game with the following: E=\frac{1}{6}*2- \frac{5}{6} *1. In general, the formula is E= \sum{p*V} where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=\frac{1}{6}v -\frac{5}{6} =0. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector.  Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
8 0
3 years ago
Read 2 more answers
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