Answer:
40.20cm approx
Step-by-step explanation:
Step one
given data
We are told that the dimension of a computer screen
diagonal= 52 cm
height= 33cm
Length = ?
Required
The length of the base of the screen
Step two
Let us use Pythagoras theorem to find the length of the base
Hyp^2= Opp^2+ Adj^2
52^2= 33^2+ L^2
2704= 1089+L^2
L^2= 2704-1089
L^2= 1615
L=√1615
L= 40.20cm approx
<u>The length is 40.20cm approx.</u>
9514 1404 393
Answer:
48 ft
Step-by-step explanation:
For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.
t = -48/(2(-16)) = 1.5
Then the maximum height is ...
f(1.5) = (-16·1.5 +48)1.5 +12 = (24·1.5) +12
f(1.5) = 48
The maximum height the object will reach is 48 feet.
8+2k=4k+4
8-4=4k-2k I placed the like terms on each side.
4=2k Simplify
4/2=k Leave the variable a side
2 = k
4x60=240
3x80=240
5x48=240
Answer 240
Hope that helps!
Answer:
Step-by-step explanation:

24x=48
x=2