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3 years ago

A zoo has 15 toucans and 60 parrots. what is the ratio of the Number of toucans to the number of parrots at the zoo?

Mathematics

2 answers:

Daniel [21]3 years ago

5 0

Answer:

1:4

Step-by-step explanation:

A ratio can be written like this: 15:60, but it can also be written as the fraction 15/60, which can be simplified to 1/4, or 1:4.

Nimfa-mama [501]3 years ago

4 0

Answer:

1:4

Step-by-step explanation:

We have been given that a zoo has 15 toucans and 60 parrots. We are asked to find the ratio of the number of toucans to the number of parrots at the zoo.

First of all we will represent our given quantities as fraction.

$\frac{\text{Toucans}}{\text{Parrots}}=\frac{15}{60}$

Now we will reduce our fraction to lowest terms.

$\frac{\text{Toucans}}{\text{Parrots}}=\frac{15\cdot 1}{15\cdot 4}$

$\frac{\text{Toucans}}{\text{Parrots}}=\frac{1}{4}$

Since there are 1 toucans for every 4 parrots, therefore, ratio of toucans to parrots is 1:4.

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Which of the following equations is of a parabola with a vertex at (3, 0)?

bixtya [17]

Answer:

D. y = (x - 3)²

Step-by-step explanation:

The parabola formula in vertex form is:

y = a(x - h)² + k

where the vertex is located at (h, k). Replacing with vertex (3, 0) we get:

y = a(x - 3)² + 0

y = a(x - 3)²

In all possible options the leading coefficient <em>a</em> is equal to one. Therefore:

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2 years ago

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Luda [366]

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3 years ago

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w

VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) $Fmax=100Hz$

b) $Fmin=0Hz$

c) $F_r=0.0313$

Step-by-step explanation:

From the question we are told that:

Time $t=32sec$

Frequency $F=200Hz$

Segments $\mu=5$

Generally the equation for Frequency Range is mathematically given by

$Fmax=\frac{F}{2}$

$Fmax=100Hz$

Therefore

a) $Fmax=100Hz$

b) $Fmin=0Hz$

Generally the equation for Frequency Resolution is mathematically given by

$F_r=\frac{F}{N}$

Where

N=The Total dat points

N=Sampling Frequency *Time

$N=200*32$

$N=6400$

Therefore

$F_r=\frac{200}{6400}$

$F_r=0.0313$

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2 years ago

(2a^3)(4a^6)(2a^3)^6

hodyreva [135]

16a^18 is the answer for what you typed

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2 years ago

the product of 2 consecutive positive into is 1,332. Explain how you can write and solve a quadratic equation to find the value

Dominik [7]

Let the smaller one is x so the larger is x+1
x(x+1)=1332
x^2+x=1332
x^2 +x -1332 =0
(x - 36)(x + 37) =0
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therefor the larger integer is either 37 or -36

8 0

2 years ago

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