Consider a sample containing 1.70 mol of an ideal diatomic gas.
1 answer:
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Answer:
the initial velocity of the ball is 104.67 m/s.
Explanation:
Given;
angle of projection, θ = 60⁰
time of flight, T = 18.5 s
let the initial velocity of the ball, = u
The time of flight is given as;
Therefore, the initial velocity of the ball is 104.67 m/s.
The length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m.The length of the spring by the letter x.
<h3>What is the potential energy of the spring?</h3>The energy is stored in the spring when it is stretched or compressed by some length. It is the product of mass, gravity and distance compressed or stretched. Mathrmatically it is given by;
PE=mgh
The given data in the problem is ;
m is the mass of the block is 0.5 kg height,
h is the height is released is 0.7 m
x initial length of the spring = 0.13 m.
K is the force constant of the spring = 1180 N/m.
By the law of conservation of energy,
The potential energy of the spring gets converted
Hence the length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m
To learn more about the potential energy of the spring refer to the link;