Well, it happens a few weeks ahead, then for a total of 3 hours and 40 minutes.
A heavy truck moving a 30 mph. It has more mass.
The force that keeps the puck moving is 0.25 N while the velocity of the puck is 3.7 m/s.
<h3>What is the centripetal force?</h3>
We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.
The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;
Centripetal force = Weight of object = mg
m = mass of the object
g = acceleration due to gravity
Then;
W = 0.026 Kg * 9.8 m/s^2
W = 0.25 N
To obtain the velocity of the object;
FT = mv^2/r
v = √ FT r/m
v = √0.25 * 1.4/0.026
v = 3.7 m/s
Learn more about centripetal force:brainly.com/question/11324711
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Answer:
The Force between the two charges is an attractive force of 16,000N
Explanation:
Expression for the electric force between the two charges is given by
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = - 2.0x10^-4C
q2 = + 8.0x10^-4C
r = 0.30 m
Substitute the given values in the above expression -
One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)
The attraction force is:
F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2
F= 16,000N
the electrons should be in the outer valence levels/shells.
