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densk [106]
3 years ago
8

Please select the word from the list that best fits the definition

Physics
2 answers:
lianna [129]3 years ago
7 0

Answer: No list

Explanation:

vaieri [72.5K]3 years ago
5 0

Answer:

C. convection

Explanation:

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an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the devi
andreev551 [17]

Answer: R=24.2Ω

Explanation: <u>Power</u> is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

P=V.i

P=R.i²

P=\frac{V^{2}}{R}

The resistance of the system is:

P=\frac{V^{2}}{R}

R=\frac{V^{2}}{P}

R=\frac{110^{2}}{500}

R = 24.2Ω

<u>For the device, resistance is 24.2Ω.</u>

4 0
3 years ago
At 19 ºC a volume of air takes us 9.0 mL in an expandable container. What is its volume after it is heated up to 50. ºC?
Katena32 [7]
According to Charles law, we know, at constant pressure, volume is directly proportional to temperature. 
So, <span>V/T = constant 
</span>
V₁/t₁ = V₂/t₂
V₁t₂ = V₂t₁

Here, we have: V₁ = 9 mL
V₂ = ?
T₂ = 50+272 = 323 K
T₁ = 19+273 = 292 K

Substitute their values into the expression:
9 × 323 = V₂ × 292
V₂ = 2907 / 292
V₂ = 9.95
After rounding-off to unit place value, it would be equal to 10 mL

So, In short Option C would be your correct answer.

Hope this helps!
5 0
3 years ago
A proton is moved so that its electric potential energy increases from 4.0 × 10-14 J to 9.0 × 10-14 J. The magnitude of the char
Kamila [148]

Answer:

B. 3.1 × 10^5 V

Explanation:

8 0
3 years ago
Read 2 more answers
(HELP!! 10pts) a train travels 75km in 1hr, and then 68km in 2hrs. what is its average speed?
blondinia [14]
Average speed = total distance travelled ÷ total time taken

AS = (75km + 68km) ÷ (1hr + 2hr)

As = 143km ÷ 3hr

AS = 47.66667 km/hr

AS = 47.7 km/hr (3sf)
8 0
3 years ago
An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what hap
serg [7]

An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet.  

As a result, the object's <em>mass remains the same</em>, and its <em>weight decreases</em> to 1/4 of whatever it is when the object is on the planet's surface.

8 0
3 years ago
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