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frosja888 [35]
3 years ago
8

Which equation is equivalent to the equation below?

Mathematics
1 answer:
olasank [31]3 years ago
8 0
The answer you are looking for is the letter i.
5n + 30 = 2n - 2
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WILL GIVE BRAINLIEST
Amanda [17]

════════ ∘◦❁◦∘ ════════

<h3>Answer : y = ⅚x - 3</h3>

════════════════════

<h3>Known</h3>

x1 = 6

y1 = 2

x2 = (-6)

y2 = (-8)

════════════════════

<h3>Question</h3>

Equation of the line (y = mx + c)

════════════════════

<h3>Way to do</h3>

#First, you find the gradient (m)

m =  \frac{y2 - y1}{x2 - x1}  =  \frac{(( - 8) - 2)}{(( - 6) - 6)}  =  \frac{( - 10)}{( - 12)}  =  \frac{5}{6}

#Now use the formula of equation of the line

y - y1 = m(x - x1)

y - 2 = ⅚(x - 6)

y - 2 = ⅚x - 5

y = ⅚x - 5+2

y = ⅚x - 3

════════════════════

3 0
2 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
The reflection of the point (4, 6) over the y-axis is:
Brums [2.3K]
(-4,6)
The x value changes bc since it is a reflection y cannot change and x becomes negative
8 0
2 years ago
Read 2 more answers
Please help me I'm desperate!
Alexus [3.1K]
R = ((3V)/((pi)(h^2))+h)/3
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3 years ago
Which point keeps the set of ordered pairs a function {(1,-2).(-2,4), (5,0)}
tester [92]
B (2,1) is the answer
4 0
2 years ago
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