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gladu [14]
3 years ago
5

When he graphs y = x - 2 ... will the 2 be positive or negative?

Mathematics
2 answers:
marin [14]3 years ago
8 0

Answer:

the answer should be y=-1/4

Andrej [43]3 years ago
3 0

Answer: It will be positive slope.

Step-by-step explanation: If the slope of the graph were to be negative, the equation would be... y = -x-2 instead.

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What is the SLOPE of a line PERPENDICULAR to the Given equation<br> y = 1/3x + 1
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3 years ago
What is angle hgf. If angle egf is 110 and angle hge is 3x+11 and angle hgf is 16x+4
Y_Kistochka [10]

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7 0
3 years ago
A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3
fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7

8 0
2 years ago
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