Answer:
y = 4x^5 - 12x^4 + 6x and
y = 5x^3 - 2x
Step-by-step explanation:
The system of equations that can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x are;
y = 4x^5 - 12x^4 + 6x and
y = 5x^3 - 2x
We simply formulate two equations by splitting the left and the right hand sides of the given equation.
The next step is to graph these two system of equations on the same graph in order to determine the solution(s) to the given original equation.
The roots of the given equation will be given by the points where these two equations will intersect.
The graph of these two equations is as shown in the attachment below;
The roots are thus;
x = 0 and x = 0.813
If the legs of a right triangle are a and b and the hypotnuse is c then
a²+b²=c²
so we are given
the legs are x and √7
and the hypotnuse is √19
so
x²+(√7)²=(√19)²
x²+7=19
minus 7 both sides
x²=12
sqrt both sides
x=√12
x=√(4*3)
x=(√4)(√3)
x=2√3
Answer:
The answer is 51
Step-by-step explanation: