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3 years ago

What is the common denominator method. Pls explain with detail

Mathematics

1 answer:

matrenka [14]3 years ago

8 0

Answer:

when both bottom numbers on a fraction are the same at the lowest form

Step-by-step explanation:

example: 2/4 + 6/8 the common denomenator is 8 as both numbers go into it and you only have to times by 2 so answer would be 10/8 which is also 1 2/8

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Please help i need it

Dima020 [189]

Answer:

Mei is correct because -9 is to the left of -3 on the number line.

Step-by-step explanation:

This is because -9 is LESS than -3, when you add or subtract using negative numbers, such as 7-9, you get -2. However when you subtract 7-13, you get -6. Because you subtracted a greater number from 7, your answer is -6 is LESS than -2. This is the same with inequalities, greater negative numbers will always be smaller and smaller negative numbers will always be greater.

Hope this helps!

4 0

1 year ago

Is 19 2/9 a integer

satela [25.4K]

Answer:No

Step-by-step explanation: Integers are whole numbers that can be positive or negatives no decimals or fractions.

3 0

3 years ago

Is the square root of 33 irrational?

maks197457 [2]

I’m gonna say no since it’s 5.74 and it isn’t repeating

6 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

I need help! Really bad a math.

Alex17521 [72]

Answer:

-72

Step-by-step explanation:

Substitute -4 in the equation

h(-4) = -20 + 13(-4)

h(-4) = -20 + -52

h(-4) = -72

-72 is the final answer

8 0

3 years ago

Read 2 more answers