Question

In 10000$ in 12%intrest for 2 years how much interest you get??​

Answer 1

Here,

amount (p) =10,000$

Time period (t)=2 years

Rate of interest (r)=12%

So,Intrest (I)

we know that,

$\boxed{ I=\dfrac{p×t×r}{100 }$

According to the question,

I=⠀$\tt{\dfrac{10000×12×2}{100} }$ ⠀

=$\tt{\dfrac{\cancel{10000}×12×2}{\cancel{100}} }$ ⠀

=$\tt{ 100×12×2 }$ ⠀

=$\tt{ 2400 }$ ⠀

So,

2400$ intrest in 10000$in 12%for 2 years

Answer 2

GIVEN :-

Principal = ₹10,000

Rate = 12%

Time = 2 Years.

TO FIND :-

How much interest he has to pay at the end of two years?

SOLUTION :-

Principal = ₹10,000

Rate = 12%

Time = 2 Years.

S.I = P×R×T/100

= 10,000×12×2/100

= 2,400

So, Interest he Has to pay at the end of two years = ₹2,400.