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dlinn [17]
3 years ago
11

Does anyone know this??

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

Y=-2x

Step-by-step explanation:

Hope this helps.

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galina1969 [7]

Answer:

X .

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Step-by-step explanation:

7 0
3 years ago
Anyone know this one I’m kinda bad at math lol
swat32

Answer:

1/ 9^5

Step-by-step explanation:

When dividing exponents with the same base, subtract the exponents

9^2 / 9^7

9 ^ (2-7)

9^ -5

We know that a^ -b = 1/ a^b

1/ 9^5

8 0
3 years ago
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Difference between x and y?
Simora [160]
X is horizontal and it always goes first and y is vertical and it always goes
Last
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3 years ago
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How do write fifty and six hundredths in standard form
BaLLatris [955]
Well before the descimal its 5,600 after decimal is 0.56
5 0
4 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
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