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BARSIC [14]
3 years ago
5

Plz plz help if u are amart

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

\underline{\boxed{s_a = 72}}

Step-by-step explanation:

first \to :    \underline{\boxed{am \: smart}} \: next \to  :  \\ let \: the \: total \: area \: be \to \: t_a = 132 \\ let \: the \: shaded \: area \: be \to \: s_a =  ? \\ let \: the \: unshaded \: area \: be \to \: u_a  =l \times b \\but \to :  \\ t_a = s_a + u_a \\ s_a = t_a - u_a \\ s_a = 132 - (l \times b) \\ s_a = 132 - (6 \times 10) \\ s_a = 132 - 60 \\  \boxed{s_a = 72}

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Step-by-step explanation:

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4 years ago
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bija089 [108]

Answer:

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To solve for x, cross multiply:

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3 years ago
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3 years ago
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