The third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.
We are given that:
2nd term of geometric progression = 1 / 18
5th term = 4 / 243
Now, we can also write it as:
2nd term = a r ( where r is the common ratio and a is the initial term.)
a r = 1 / 18
5th term = a r⁴
a r⁴ = 4 / 243
Now divide 5th term by 2nd term, we get that:
a r⁴ / a r = ( 4 / 243 ) / ( 1 / 18 )
r³ = 72 / 243
r³ = 8 / 27
r = ∛ (8 / 27)
r = 2 / 3
3rd term = a r²
a r² = a r × r
= 1 / 18 × 2 / 3
3rd term = 1 / 27
Therefore, the third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.
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Your question was incomplete. Please refer the content below:
The 2nd and 5th term of a GP are 1/18 and 4/243 respectively find the 3rd term
Answer:
477.28cu m
Step-by-step explanation: R (8) x3.14 (pi) is 25.12, 25.12x19=477.28
The answer is 0.875
0.56÷0.64=0.875
Let's consider what the x and y values represent. x represents the time at which an object is moving in relation to its height represented by y. So, we already know a restriction on y, y >= 0.
Now, let's consider each case of scenarios.
For A) the time of a falling object is -4 in relation to it being dropped at a height of 1 means the falling object is traveling back in time. But that doesn't really make any sense at all. How does an object travel back in time?
B, C and D are all valid because they fit the domain and range. In essence, they make sense.
