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dangina [55]
3 years ago
13

Define the variables for the situation. Then enter an equation.

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer:

A= L + 5

Step-by-step explanation:

Andrews class is equal to Lauren's class and there are more 5 students

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The 2nd and 5th terms of a gp are 1/18 and 4/243 respectively. Find
Viktor [21]

The third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.

We are given that:

2nd term of geometric progression = 1 / 18

5th term = 4 / 243

Now, we can also write it as:

2nd term = a r ( where r is the common ratio and a is the initial term.)

a r = 1 / 18

5th term = a r⁴

a r⁴ = 4 / 243

Now divide 5th term by 2nd term, we get that:

a r⁴ / a r = ( 4 / 243 ) / ( 1 / 18 )

r³ = 72 / 243

r³ = 8 / 27

r = ∛ (8 / 27)

r = 2 / 3

3rd term = a r²

a r² = a r × r

= 1 / 18 × 2 / 3

3rd term = 1 / 27

Therefore, the third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.

Learn more about geometric progression here:

brainly.com/question/24643676

#SPJ4

Your question was incomplete. Please refer the content below:

The 2nd and 5th term of a GP are 1/18 and 4/243 respectively find the 3rd term

6 0
1 year ago
Read 2 more answers
A cylinder has a base radius of 8 meters and a height of 19 meters. What is its volume in cubic meters, to the nearest tenths pl
77julia77 [94]

Answer:

477.28cu m

Step-by-step explanation: R (8) x3.14 (pi) is 25.12,  25.12x19=477.28

5 0
2 years ago
A group of 15 friends take a trip to a water park. The total price of the trip is $599.85 before any discounts. The total price
Contact [7]

Answer:

25%

Step-by-step explanation:

7 0
3 years ago
Greg was dividing 0.56 by 0.64
MrRissso [65]
The answer is 0.875
0.56÷0.64=0.875
7 0
3 years ago
Louis used a quadratic equation to model the height, y, of a falling object x seconds after it is dropped. which ordered pair ge
n200080 [17]

Let's consider what the x and y values represent. x represents the time at which an object is moving in relation to its height represented by y. So, we already know a restriction on y, y >= 0.

Now, let's consider each case of scenarios.

For A) the time of a falling object is -4 in relation to it being dropped at a height of 1 means the falling object is traveling back in time. But that doesn't really make any sense at all. How does an object travel back in time?

B, C and D are all valid because they fit the domain and range. In essence, they make sense.

5 0
3 years ago
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