5 I think ................................................
Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.


Answer:
10 miles
Step-by-step explanation:
Right triangle
a^2 + b^2 = c^2
6^2 + 8^2 = c^2
36 + 64 = c^2
Sqrt 100 = c
C = 10
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