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ollegr [7]
2 years ago
5

The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another po

int that must lie on the graph of y = f(x).
Mathematics
1 answer:
qaws [65]2 years ago
3 0

You are missing an entire paragraph of information that is needed to solve what you've actually posted. Luckily for you, I answered this question once before.

Here is the ENTIRE QUESTION:

The graph of y = f(x) is a parabola whose vertex is at (1, -2). The graph of y = f(x - 3) is also a parabola. Where is the vertex of the graph of y = f(x-3)? Write your answer as an ordered pair.

Solution:

The "f( x - 3)" shifts the the graph of f(x) to the right by 3 units.

So...the vertex of f(x - 3) is ( 4, - 2).

2. The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).

Here is the solution you are looking for.

If the graph has an axis of symmetry of x = 5 and (8, -7) is on the graph, we simply add 3 to 5 to get (8,-7). Afterwards, we must subtract 3 from 5 to get : (5 - 3, -7) = (2, -7) is also on the graph.

Notice that the y-coordinate is unaffected. Cool, right?

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Dimetri says that a function that is made of terms where the variables is raised only to an odd power will be an odd function.Do
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Here we want to study the relation between the exponents in a polynomial function and the "odd" property of functions.

We will see that Dimetri is correct.

-------------------------------

We start by defining an odd function as a function such that:

f(-x) = -f(x).

Now, let's see a simple function with only odd exponents.

f(x) = a*x  (the exponent is 1, so it is odd).

if we evaluate this in x = 1, we get:

f(1) = a

If we evaluate this in x = -1, we get:

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Then this is odd.

Now let's see a more general case and why Dimetri is correct.

For the rule of signs, when we multiply 2 negative numbers, the <u>product is positive.</u>

So always that we have an even exponent on a negative number, the outcome will be positive.

This does not happen for odd exponents, because we can't separate all the products in groups of 2, thus if we take the <u>odd exponent of a negative number, the outcome is negative</u>.

Then for functions with only odd exponents, the <u>outcome for evaluating the function in a given input is exactly the opposite of evaluating the same function with the opposite input</u>.

This means that the function is odd.

Again, note that this only happens if the function only has odd exponents.

If you want to learn more, you can read:

brainly.com/question/15775372

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