Hope this helps you out more. If you need more explaining just comment on my answer and i help you out even more deeper into the question.
If you are solving for a: it equals 3
distribute: 5a + 5=2a +14
get rid of extra number on one side: 5a=2a +9 (subtract 5 from both sides)
get rid of the other variable: 3a=9 (subtract 2a from both sides)
divide to isolate a: 3a/3=9/3 (divide by three on both sides)
answer= a=3
<u>Answer:</u>
P (S∩LC) = 0.03
<u>Step-by-step explanation:</u>
We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.
Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.158 = P(S∩LC) / 0.19
P (S∩LC) = 0.158 × 0.19 = 0.03
Answer:
7
Step-by-step explanation:
We can represent this with an equation. a+b = 28, and a = 7 + 2b. We can substitute the second equation into the first equation to get 7 + 2b + b = 28, or 7 + 3b = 28. Subtract 7 from both sides and we get 3b = 21. Divide both sides by 3 and we get b = 7. Therefore, the second number is 7.