21 they have too be right next to each other and threy have too be right
95
Step-by-step explanation:
pleas make me the brainlist
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer
C: 4 is the right answer
Step-by-step explanation:
Given
a1 = -3
a15 = 53
We know that explicit formula for the arithmetic sequence is:

For the 15th, term it will be

Adding 3 on both sides

Dividing both sides by 14

Hence,
C: 4 is the right answer
Keywords: Arithmetic sequence, Common Difference
Learn more about arithmetic sequence at:
#LearnwithBrainly
Answer:
It is divisible by 11 and (a + b) !
Step-by-step explanation:
Given a two digit number
, the digits written in reverse order is
.
Note that a two digit number ab = 10a + b.
For example: 24 = 10(2) + 4
Similarly, ba = 10(b) + a
Now, the sum of the numbers ab and ba = 10a + b + 10b + a
= 11a + 11b
= 11(a + b)
Hence, the sum of any two digit number ab and the reverse of the number ba, is divisible by 11 and (a + b).
Hence, proved.