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Gnesinka [82]
3 years ago
10

If you make $11.25/hour, how many hours will you need to work to earn $416.25? Please explain how you figured this out.

Mathematics
2 answers:
nikklg [1K]3 years ago
8 0

Answer:

37 hours.

Step-by-step explanation:

Since you need $416.25 start with that. Then divide by $11.25 to see how many hours you need to work. 416.25 divided by 11.25 is 37.

Andreas93 [3]3 years ago
7 0
37 hours, you divide 11.25 by 416.25
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Layla takes 190 milligrams of an antibiotic. Every hour, her body breaks down 10% of the drug. How much will be left after 5 hou
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Step-by-step explanation:

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5 0
2 years ago
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?
Maru [420]

C: 4 is the right answer

Step-by-step explanation:

Given

a1 = -3

a15 = 53

We know that explicit formula for the arithmetic sequence is:

a_n=a_1+(n-1)d

For the 15th, term it will be

a_{15}=-3+(15-1)d\\53=-3+14d

Adding 3 on both sides

53+3 = -3+3 + 14d\\56 = 14d

Dividing both sides by 14

\frac{56}{14}=\frac{14d}{14}\\d=4

Hence,

C: 4 is the right answer

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/12896802
  • brainly.com/question/12973601

#LearnwithBrainly

4 0
3 years ago
Prove that the sum of ab and ba is divisible by the sum of a and b
Likurg_2 [28]

Answer:

It is divisible by 11 and (a + b) !

Step-by-step explanation:

Given a two digit number $ ab $, the digits written in reverse order is $ba $.

Note that a two digit number ab  = 10a + b.

For example: 24 = 10(2) + 4

Similarly, ba = 10(b) + a

Now, the sum of the numbers ab and ba = 10a + b + 10b + a

= 11a + 11b

= 11(a + b)

Hence, the sum of any two digit number ab and the reverse of the number ba,  is divisible by 11 and (a + b).

Hence, proved.

5 0
3 years ago
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