Which of the following equations are perpendicular

Mathematics

1 answer:

Andrews [41]3 years ago

6 0

I think it’s the third one but I’m not %100 sure

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Solve the equations if possible * -5×=×+6(1-×) *(2×-5)²=(2×-1)(2×+1)-10(2×-1)

Allushta [10]

-5x = x + 6(1-x)

-5x = x + 6(1) + 6(-x)
-5x = x + 6 -6x
-5x = x - 6x + 6
-5x = -5x + 6
-5x + 5x = 6
0 = 6 Not equal. No solution.

(2x-5)² = (2x-1)(2x+1) -10(2x-1)
(2x-5)(2x-5) = (2x-1)(2x+1) - 20x + 10
2x(2x-5)-5(2x-5) = 2x(2x+1)-1(2x+1) - 20x + 10
4x² - 10x -10x + 25 = 4x² + 2x - 2x -1 - 20x + 10
4x² - 20x + 25 = 4x² - 20x - 1 + 10
4x² - 20x + 25 = 4x² - 20x - 9

Not equal. No solution.

8 0

2 years ago

Please help I’m confused

Amanda [17]

Answer:

First 3 boxes down are Vertical, Complementary, Supplementary . Second 3 Boxes Down Are add up to 90 degrees, add up to 180 degrees, and are congruent.

I hope this helps :)

5 0

2 years ago

Read 2 more answers

Identify the solutions of the inequality 11 ≤ p + 5.

ale4655 [162]

all real numbers greater than or equal to 6

4 0

3 years ago

I need answer ASAP Please

raketka [301]

Answer:

6x10^8/2x10^8

= 3 times

4 0

3 years ago

The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?

horsena [70]

Step-by-step explanation:

$a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\$

Subtracting equation (2) from equation (1)

$a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\$

Substituting d = - 3 in equation (1), we find:

$a + 9\times (-3)= - 27\\\\\therefore a - 27 = - 27\\\\\therefore a = 27- 27\\\\\huge \red {\boxed {\therefore a = 0}}\\\\$

Hence, first term is zero.

3 0

3 years ago