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Ierofanga [76]
3 years ago
6

Find the radius of a sphere with a volume of 26, 2440 cubic inches

Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Answer:

8.7304 x 1010

Step-by-step explanation:

I think its that >_<

The last 10 is supposed to be on top to the right of the 10

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Plz help w this math problem
Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

{ \tt{x = 2a \sqrt{t} }} \\  \\ { \tt{ \sqrt{t}  =  \frac{x}{2a} }} \\  \\ { \boxed{ \tt{t =  \frac{ {x}^{2} }{4 {a}^{2} } }}}

• then find y:

{ \tt{y =  {ar}^{2}  - 2at}} \\  \\ { \tt{y =  {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\  \\ { \boxed{ \tt{y =  {ar}^{2} -  \frac{ {x}^{2} }{2a}  }}}

6 0
3 years ago
HELPPPPPP<br><br> what is x minus 1 x-1
Evgesh-ka [11]

Answer:

-1

Step-by-step explanation:

x - 1x - 1

1x = x

x - x -1

x - x = 0

0 - 1 = -1

-1

3 0
3 years ago
Help please
mezya [45]

Answer:

Step-by-step explanation:

Remark

My guess is that what is confusing you is not what you have to do, but why it is disguised as g(n)

What you are doing in effect is setting up a table. You are also not certain where the table starts. And that is a problem. I will start it at zero, but it might be 1.

zero

n = 0

g(0) = 34 - 5*0

g(0) = 34

One

n = 1

g(1) = 34 - 5*1

g(1) = 34 - 5

g(1) = 29

Two

g(2) = 34 - 5*2

g(2) = 34 - 10

g(2) = 24

Three

g(3) = 34 - 5*3

g(3) = 34 - 15

g(3) = 19

Four

g(4) = 34 - 5*4

g(4) = 34 - 20

g(4) = 19

Answer

0      1       2       3      4

34  29     24     19     14

7 0
2 years ago
8x+21=3 need the answer please
GarryVolchara [31]

Answer:

x=-\frac{9}{4}

Step-by-step explanation:

<u>Step 1:  Subtract 21 from both sides</u>

8x + 21 = 3

8x + 21 - 21 = 3 - 21

8x = -18

<u>Step 2:  Divide 8 from both sides</u>

8x = -18

\frac{8x}{8}=-\frac{18}{8}

x=-\frac{9}{4}

Answer:  x=-\frac{9}{4}

3 0
1 year ago
The radioactive substance polonium-210, with a half-life of 138.39 days, is present in tobacco. Suppose that the soot in an ex-s
Ksju [112]

Answer:

16.07 milligrams

Step-by-step explanation:

From the question,

Using the formula of radioactive decay,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original mass of the polonium-210, R' = Final mass of polonium-210 after decaying, a = Total disintegration time, b = half life of polonium-210.

Make R' the subject of the equation

R' = R/(2ᵃ/ᵇ)................ Equation 2

Given: R = 100 milligrams, a = 1 years = 365 days, b = 138.39 days

Substitute these values into equation 2

R' = 100/(2³⁶⁵⁰⁰/¹³⁸³⁹)

R' = 100/(6.222)

R' = 16.07 milligrams of plonium-210

3 0
2 years ago
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