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zubka84 [21]
3 years ago
6

Suppose y varies directly with x when x is 4, y is 32. What is y when x is -2

Mathematics
1 answer:
omeli [17]3 years ago
3 0

Step-by-step explanation:

Since y varies directly with x,

y = kx, where k is a real constant.

When x = 4, y = 32.

=> (32) = (4)k, k = 8.

Therefore when x = -2,

y = kx = (8)(-2) = -16.

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2x+2(1960/x)=200 please help for math hw
sp2606 [1]

Two solutions:

1. x =(100-√2160)/2=50-6√ 15 = 26.762

2. x =(100+√2160)/2=50+6√ 15 = 73.238

3 0
3 years ago
If sine theta equals three over four, what are the values of cos θ and tan θ?
ratelena [41]

Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.

a²+b²=c²

a²=c²-b²

a²=4²-3²

a²=16-9

a²=7

a=√7

Then Cos ∅= opposite/ adjacent

=√7/4

Then Tan ∅ = opposite/adjacent

=3/√7

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven.

7 0
3 years ago
The dimensions of a cube are doubled. The volume of the enlarged cube is how many times the volume of the original cube?
Elza [17]
The volume is multiplied by 8. For example if you have a 1x1x1 cube the volume is 1. If you have a 2x2x2 cube the volume is 8. If you have a 4x4x4 the volume is 64.
5 0
3 years ago
Read 2 more answers
WHAT IS TRUE ABOUT THE HEIGHT OF THE RECTANGLE
scZoUnD [109]

Answer:

It is totaly based on the diagram

6 0
3 years ago
Read 2 more answers
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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