Answer:
Yes. The fact that an object moves at constant velocity implies that its speed is also constant. Note that the converse statement isn't necessarily true.
Explanation:
Velocity is a vector. For two vectors to be equal to each other,
- their magnitudes (sizes) need be the same, and
- they need to point in the same direction.
In motions, the magnitude of an object's velocity is the same as its speed.
If the car moves with a constant velocity, that means that
- the magnitude of its velocity, the speed of the car, is constant;
- also, the direction of the car's motion is also constant.
In other words,
.
Note that the arrow here points only from the velocity side to the speed side. It doesn't point backward because knowing that the speed of an object is constant won't be sufficient to prove that the velocity of the object is also constant. For example, for an object in a uniform circular motion, the speed is constant but the direction keeps changing. Hence the velocity isn't constant.
To solve this problem, we must basically count the total energy lost converting all the values given in the international system.
The energy loss is given by both 124KJ and 124food heats.
Since the energy conversion we know that 1 food calories is equal to 4,184J. So:
Therefore the total energy lost will be
Therefore the total energy lost to the surroindings in form of heat is 124.518kJ
Answer:
Explanation:
When a force is applied to an object over a certain period of time, it is said to apply an impulse to the object. The magnitude of the impulse is given by:
J=F*Δt
When an impulse is provided to an object, the momentum of the object will change, as in:
J=Δp=
So given:
Initial momentum
Applied force
J=
F*Δt=
Answer:
y_red / y_blue = 1.11
Explanation:
Let's use the constructor equation to find the image for each wavelength
1 /f = 1 /o + 1 /i
Where f is the focal length, or the distance to the object and i the distance to the image
Red light
1 / i = 1 / f - 1 / o
1 / i_red = 1 / f_red - 1 / o
1 / i_red = 1 / 19.57 - 1/30
1 / i_red = 1,776 10-2
i_red = 56.29 cm
Blue light
1 / i_blue = 1 / f_blue - 1 / o
1 / i_blue = 1 / 18.87 - 1/30
1 / i_blue = 1,966 10-2
i_blue = 50.863 cm
Now let's use the magnification ratio
m = y ’/ h = - i / o
y ’= - h i / o
Red Light
y_red ’= - 5 56.29 / 30
y_red ’= - 9.3816 cm
Light blue
y_blue ’= 5 50,863 / 30
y_blue ’= - 8.47716 cm
The ratio of the height of the two images is
y_red ’/ y_blue’ = 9.3816 / 8.47716
y_red / y_blue = 1,107
y_red / y_blue = 1.11
