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notka56 [123]
3 years ago
6

The average energy per unit time per unit area that reaches the upper atmosphere of the Earth from the Sun, called the solar con

stant, is 1.47 kW/m2. Because of absorption and re- flection by the atmosphere, about 0.9 kW/m2 reaches the surface of the earth on a clear day. How much energy is collected during 1 h of daylight by a window that measures 1.1 m by 1.5 m? The window is on a mount that rotates, keeping the window facing the sun so the sun's rays remain perpendicular to the window. Answer in units of MJ.
Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer: 5.34 MJ

Explanation: The window is a rectangle with area:

A = 1.1(1.5)

A = 1.65 m²

We know that only 0.9 kW/m² reaches Earth so:

P = 0.9\frac{kW}{m^{2}}(1.65)m^{2}

P = 1.485 x 10³ W

Watts is an unit of Power and it can also be written as J/s.

An hour has 3600s or 3.6 x 10³s, so:

E = 1.485 x 10³ \frac{J}{s}(3.6 x 10³s)

E = 5.346 x 10⁶ J

Mega is equal to 10⁶, then:

E = 5.35 MJ

A 1.1 m by 1.5 m window collects, during 1 hour of daylight, 5.35 MJ

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The blood pressure of human body is greater at the feet than at the brain. why?give reason​
SOVA2 [1]

Answer:

Gravity stronger closer to the core of the earth

Explanation:

The gravity applied to the feet is stronger than to the upper part of the body for example the brain because of the distance it is between the body part and the core of the earth where the gravity force is pulling towards. Even though the difference between the gravity force between the brain and the feet is minimal it is still a greater force at the feet than at the brain

6 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of
Monica [59]

Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

C = \frac{\epsilon _0A}{d}

C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

(c) initial energy,

U = \frac{q^{2}}{2C}

U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J

Final energy

U' = \frac{q^{2}}{2C'}

U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J

6 0
3 years ago
Two objects are in freefall. Object A experiences a gravitational force of
Vlad1618 [11]

<u>Answer:</u>

Both the objects A and B will have the same acceleration.

<u>Explanation :</u>

The objects will have the same acceleration as both are under free fall condition. When objects are under the free fall condition, the only force that acts on the object is its weight.

Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).

Therefore, here the different weight is due to the difference masses of both bodies, and not due to the different acceleration values.

3 0
3 years ago
an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a
finlep [7]

Answer:

force; distance; energy.

Explanation:

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

Impulse = force * time

An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.

Mathematically, work done is given by the formula;

Work done = force * distance

4 0
3 years ago
A squirrel is trying to locate some nuts he buried for the winter. He moves 4.3 m to the right of a stone and dogs unsuccessfull
krek1111 [17]

Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

8 0
3 years ago
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