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Nastasia [14]
3 years ago
15

Steve connected a wire extension that is 3/8 foot long to another wire that is 1/2 foot long. How long is the wire with the exte

nsion?
Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

<u>7/8 feet</u>

Step-by-step explanation:

In order to add two frctions you need to make their denominator the same,

3/8 can be kept as it is and we can multiply the top and bottom of 1/2 by 4 in order to ger 4/8. Now it is easier to add together,

3/8 + 4/8= <u>7/8</u>

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I needed help but then i found the answer
Alenkinab [10]

1/2 × 5 2/3 × 3 = 5

the 2's cancel giving you 5 × 1/3 × 3

then the 3's cancel giving you 5 × 1

and 5 × 1 is 5.

4 0
3 years ago
A baseball player on a professional baseball team has 207 hits in 575 at-bats. What
Vika [28.1K]

Answer:

9/25

Step-by-step explanation:

find a number that both the top and bottom are divisible by,

23 is the greatest common division we can make such that the top and bottom remain whole numbers

so,

\frac{207 }{575} ÷23

=(207/23)÷(575/23)

=\frac{9}{25}

4 0
2 years ago
Use the following figure to answer the question. if line t is perpendicular to both line l and m then 1 and 2 are both right ang
stepan [7]

It's true, assuming that angles 1 and 2 are are at the intersection of line t and l/m

8 0
3 years ago
The pH level of a solution measures how acidic or basic the solution is. Values between 0 and 7 are considered acidic while valu
Furkat [3]

Answer:

  about 2.47

Step-by-step explanation:

Your calculator will tell you ...

  -\log{(3.4\times 10^{-3})}\approx 2.4685\approx\bf{2.47}

4 0
3 years ago
7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t
Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

\frac{x^a}{x^b}=x^{a-b}

x^0=1

(x^a)(x^b)=x^{a+b}

x^{-a}=\frac{1}{x^a}


\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=

\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=

\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=

(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=

(7^{-5-(-5)})(2^{0-3})=

(7^0)(2^{-3})=

\frac{1}{2^3}=

\frac{1}{8}

7 0
3 years ago
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