Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.
The circle goes thru the given points <span>(3,-4) And (3,5). Since the x-coordinate does not change, the diameter lies right on the vertical line x=3. Since the vertical distance between these points is 5-(-4), or 9, the radius is 9/2.
The standard eq'n of a circle is (x-h)^2 + (y-k)^2 = r^2
Let's subst. what we know: we get (x-3)^2 + (y-1/2)^2 = (9/2)^2. Note that y = 1/2 is halfway between y=-4 and y=5.</span>
The answer is C
call the length is a => the diagonal is a+1
11^2 + a^2=(a+1)^2
<=> 121 + a^2=a^2 + 2a +1
<=>120=2a
<=> a=60
I think it would be conditional, because B depends on A. Of A is false, then B isn’t possible, making it conditional.
Log=13
t=4
So, this is because they already given you t because the four is on front of it that gives you your value. From there you will proceed to j7st do the math in your parentheses. You should get log=(1) & log=(13) because 1 times anything is that number just use the inverse of each would be eachother. So, 1x13 is the same as 13x1
