-- reduce the length of a wire to 1/2 . . . cut the resistance in half
-- reduce the diameter to 1/4 . . . reduce the cross-section area by (1/4²) . . . increase the resistance by 16x .
-- R2 = (R1) · (1/2) · (16) = 8 · R1
<em>-- R2 / R1 = 8</em>
The correct answer is A. 250N
Work is a product of force and distance.
That is, work done=force×distance
Therefore substituting for the values in the question:
500J=force×2m
force= 500Nm/2m=250N
another unit for work done is Nm as force as the SI unit of force is newtons and distance in meters
Answer:
18 N/C
Explanation:
Given that:
Electric field constant, k = 9*10^9 N/c
Distance, r = 10^-8 m
Dipole moment, p = 10^-33
Using the relation for electric field due to dipole :
E = [2KP / r³]
E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3
E = (18 * 10^9 * 10^-33) ÷ 10^-24
E = [18 * 10^(9-33)] ÷ 10^-24
E = (18 * 10^-24) / 10^-24
E = 18 * 10^-24+24
E = 18 * 10^0
E = 18 N/C
Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.
The best and most correct answer among the choices provided by the question is <span>f(t) = −70 cos pi over 6t + 110</span><span>.
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Hope my answer would be a great help for you.
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