here tension in the string is counter balanced by weight of block of mass m1
so we can say
now on the other side the block which is placed on the inclined plane
we can say that component of weight of the block and friction force is counter balanced by tension force
now we can plug in all values to find the friction force
so it will have 0.83 N force on it due to friction
now to find the friction coefficient
here we know that
now from above equation
so friction coefficient will be 0.38
Answer:
$900
Explanation:
Step 1: Our output value is 9000.
Step 2: We represent the unknown value with x.
Step 3: From step 1 above,$9000=100\%$
Step 4: Similarly, x=10%
Step 5: This results in a pair of simple equations:
$9000=100
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
\frac{9000}{x}=\frac{100\%}{10\%}
Step 7: Again, the reciprocal of both sides gives
\frac{x}{9000}=\frac{10}{100}$
\Rightarrow x=900$
Therefore, $10\%$ of $9000$ is $900$
Answer:
d=√[(x₂ - x₁)² + (y₂ - y₁)²]
Answer:Poopy-di scoop
Scoop-diddy-whoop
Whoop-di-scoop-di-poop
Poop-di-scoopty
Scoopty-whoop
Whoopity-scoop, whoop-poop
Poop-diddy, whoop-scoop
Poop, poop
Scoop-diddy-whoop
Whoop-diddy-scoop
Whoop-diddy-scoop, poop
Explanation: