car travels 13 meters per second accelerates to 25 meters per second, how far did it travel in 6 seconds

Object A has mass m and is traveling forward with speed v. Which set of changes to object A will not affect its momentum?

lara [203]

The situation that will not affect momentum is:

mass reduced to 0.5m, speed increased to 2v

Explanation:

The momentum of an object is defined as

$p=mv$

where

m is the mass of the object

v is its velocity

Let's call m the initial mass of object A and v its initial velocity, so its initial momentum is

$p=mv$

Let's now analyze each situation to see how the momentum changes:

- mass reduced to 0.5m, speed increased to 2v

New momentum is:

$p'=(0.5m)(2v)=mv=p$ --> so momentum is unchanged

- mass reduced to 0.25m, speed increased to 1.25v

New momentum is:

$p'=(0.25m)(1.25v)=0.31mv = 0.31 p$ --> momentum has changed

- mass increased to 2m, speed increased to 2v

New momentum is:

$p'=(2m)(2v)=4mv=4p$ --> momentum has changed

- the direction of velocity reversed, speed kept at v

Since momentum is a vector, the direction also matters: therefore, if the direction of the velocity changes, the direction of the momentum changes as well, so the momentum has changed.

So the only situation that will not affect the momentum is

mass reduced to 0.5m, speed increased to 2v

Learn more about momentum:

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#LearnwithBrainly

5 0

4 years ago

A 77 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.18 T field, starting with the normal of the

Tasya [4]

Answer:

a) fem = 5.709 V, b) t = 0.196 s, c) t = 0.589 s, d) T = 0.785 s

Explanation:

This is an exercise in Faraday's law

fem= - N $\frac{d \Phi _B}{dt}$

fem = - N $\frac{d \ (B A cos \theta)}{dt}$

The magnetic field and the area are constant

fem = - N B A $\frac{d \ cos \ \theta}{dt}$

fem = - N B A (-sin θ) $\frac{d \theta}{dt}$

fem = N B (π d² / 4) sin θ w

fem= $\frac{\pi }{4}$ N B d² w sin θ

with this expression we can correspond the questions

a) the peak of the electromotive force

this hen the sine of the angle is 1

sin θ = 1

fem = $\frac{\pi }{4}$ 77 1.18 0.10² 8.0

fem = 5.709 V

b) as the system has a constant angular velocity, we can use the angular kinematics relations

θ = w₀ t

t = θ/w₀

Recall that the angles are in radians, so the angle for the maximum of the sine is

θ= π/2

t = $\frac{\pi }{2} \ \frac{1}{8}$

t = 0.196 s

c) for the electromotive force to be negative, the sine function of being

sin θ= -1

whereby

θ = 3π/ 2

t = $\frac{3\pi }{2} \ \frac{1}{8}$

t = 0.589 s

d) This electromotive force has values that change sinusoidally with an angular velocity of

w = 8 rad / s

angular velocity and period are related

w = 2π / T

T = 2π / w

T = 2π / 8

T = 0.785 s

6 0

3 years ago

The term wavelength refers to which of the following?

svlad2 [7]

The answer is C hope it helps

5 0

3 years ago

1. In 10 seconds, a car accelerates 4 m/s/s to 60 m/s. How fast was the car going before it accelerated?

ladessa [460]

4m/s is the answer you are looking for

3 0

3 years ago

A rectangular painting measures 1.0 m tall along the y' axis and 3.0 m wide along the

Gennadij [26K]

Answer:

a) 1 m tall, 3 m wide

b) 1 m tall, 1.31 m wide

Explanation:

According to the captain of the spaceship, the dimensions of the picture is the same i.e 1.0 m tall along the y' axis and 3.0 m wide along the x' axis.

b) The dimensions of the picture as seen by an observer on the Earth along the y axis will remain the same, 1.0 m tall, for the direction of the y axis is perpendicular to the spaceship movement.

The dimensions of the picture as seen by an observer on the Earth along the x axis will reduce if we are to go by the Lorentz contraction:

L(x) = L(x)' * √[1 - (v²/c²)]

where

L(x)' = the dimensions of the picture along the x axis on the spaceship,

v² = the speed of the spaceship and c² = the speed of light in the vacuum.

On substituting, we have

L(x) = 3 * √[1 - (0.81c²/c²)]

L(x) = 1.31 m

8 0

3 years ago