Answer: A train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.
Explanation: To find the answer, we need to know about uniformly accelerated motion.
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How to solve the problem?</h3>
- We have to find the distance travelled by the train.
- Substituting values, we get,
- We have the equation for final velocity as,
Thus, we can conclude that, a train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.
Learn more about the uniformly accelerated motion here:
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Refer to the diagram shown below.
The following discussion assumes a simplistic analysis that ignores air resistance and variations in the terrain that the missile travels over.
Let the launch velocity be V₀ at an angle of θ relative to the horizontal.
The horizontal component of velocity is V₀ cosθ.
If the time of flight is
, then
where r = the range of the missile.
Also, the time, t, when the missile is at ground level is given by
where g = acceleration due to gravity.
t = 0 corresponds to when the missile is launched. Therefore
Therefore
Typically, θ=45° to achieve maximum range, so that
This analysis is more applicable to a scud missile rather than a powered, guided missile.
Answer:
Usually, θ=45°
<span>No. Work is not done if you carry a book across the room
at a constant velocity?
The force applied is perpendicular to the direction of motion. (C)</span>
We use the formula
to find the initial velocity
We have:
Initial velocity (u) = 12 m/s
Acceleration (a) = 14 m/s²
Distance (s) = 48 meters
We are looking to find the final velocity (v)
Substituting these values into the formula, we have:
v² = 12² + 2(14)(48)
v² = 144 + 1344
v² = 1488
v = √1488
v = 38.57 m/s