The inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
<h3>Graph of Inequality</h3>
From the question, we are to determine the inequality that represents the graph
First, we will assume the inequality is a straight line and we will determine the equation of the line
From the graph, we have two points on the line
(0, -2) and (5, -1)
Using the formula for the equation of a line with two given point
(y - y₁)/(x -x₁) = (y₂ - y₁)/ (x₂ - x₁)
x₁ = 0
y₁ = -2
x₂ = 5
y₂ = -1
Thus,
(y - -2)/(x - 0) = (-1 - -2)/ (5 - 0)
(y +2)/(x - 0) = (-1 + 2)/ (5 - 0)
(y +2)/(x ) = 1/ 5
5(y + 2) =1(x)
5y + 10 = x
5y = x - 10
y = 1/5(x) - 2
y = x/5 - 2
Now,
Since the solution is below the line and the line is dotted
The inequality becomes
y < x/5 -2
OR
5y < x - 10
Hence, the inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
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Answer:
132.4
Step-by-step explanation:
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<span>(t) = 0 gives
</span><span>-24t + 60 = 0
</span><span>t = 2.5
</span><span>For this t, the second derivative s"(t) = -24 is negative. And so, s(t) is maximum for t = 2.5.
</span><span>Maximum height is S = -12(2.5)^2 + 60(2.5) +8 = 233ft</span>
Answer:
16,242. 7 cm^3.
Step-by-step explanation:
We need to cut off a square piece at the 4 corners of the cardboard.
Let the length of their edges be x cm.
The volume of the box will be:
V = height * width * length
V = x(100-2x)(40-2x)
V = x(4000 - 200x - 80x + 4x^2)
V = x(4x^2 - 280x + 4000)
V = 4x^3 + - 280x^2 + 4000x
Finding the derivative:
dV / dx = 12x^2 - 560x + 4000 = 0 ( when V is a maxm or minm.)
4(3x^2 - 140x + 1000) = 0
x = 37.86, 8.80.
Looks like x = 8.80 is the right value but we can check this out be looking at the sign of the second derivative:
V" = 24x - 560, when x = 8.8 V" is negative so this is a Maximum for V.
So the maximum volume of the box is when x = 8.8 so we have
V = 8.8(100-2(8.8)(40 - 2(8.8)
= 16,242. 7 cm^3.
