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gladu [14]
3 years ago
12

Pls help me meememememmmememe

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Step-by-step explanation:

A= 4(pi)r^2

A=4(3.14159265359)13^2

A=2123.72

**I dont know if it's right or wrong.**

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Determine if the following table represents a quadratic function.
snow_tiger [21]

Answer:

<em>The options are not visible enough (See Explanation)</em>

Step-by-step explanation:

Given

x:-  1   || 2   || 3   || 4   || 5

y:-  13 || 22 || 37 || 58 || 85

Required

Determine if the function is quadratic

Calculate the difference between the values of y

Difference = 22 - 13 = 9

Difference = 37 - 22 = 15

Difference = 58 - 37 = 21

Difference = 85 - 58 = 27

<em>The resulting difference are: 9 || 15 || 21 ||  27</em>

Next; Calculate the difference between the difference of values of y

Difference = 15 - 9 = 6

Difference = 21 - 15 = 6

Difference = 27 - 21 = 6

<em>The resulting difference are: 6 || 6 || 6</em>

<em>For the function to be quadratic, the above difference must be the same and since they are the same (6), then the function represents a quadratic function.</em>

7 0
3 years ago
3x^2-5=43 how do i solve this using the square root property
slava [35]

Answer:

x = 4

x = -4

Step-by-step explanation:

bro i dont know but i hope this help a little, sorry

4 0
3 years ago
Is the sqrt of -36 a real number
Mkey [24]

Answer:

No

Step-by-step explanation:

The square root of any negative number is not a real number.

4 0
3 years ago
Read 2 more answers
Find x<br> a) 21 √2<br> b)7<br> c)21 √2/2<br> d)21 √3/2
fgiga [73]

Answer:

C

Step-by-step explanation:

Use the sine ratio in the left, right triangle to find the common side to both triangles and the exact values

sin60° = \frac{\sqrt{3} }{2} , cos45° = \frac{1}{\sqrt{2} } , thus

sin60° = \frac{opposite}{hypotenuse} = \frac{opp}{7\sqrt{3} } = \frac{\sqrt{3} }{2} ( cross- multiply )

2 × opp = 21 ( divide both sides by 2 )

opp = \frac{21}{2}

Now consider the right triangle on the right, using the cosine ratio

cos45° = \frac{adjacent}{hypotenuse} = \frac{\frac{21}{2} }{x} = \frac{1}{\sqrt{2} } ( cross- multiply )

x = \frac{21}{2} × \sqrt{2} = \frac{21\sqrt{2} }{2} → C

5 0
3 years ago
How do you do this?<br><br> I’ve been having trouble with this for the past 10 mins
xz_007 [3.2K]
Basically it's telling you what equation to use for the specific value of g(x). If x is g(2) then you would use the third equation. 2x - 5. so 2(2)-5= -1
7 0
3 years ago
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