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sveta [45]
3 years ago
15

Be able to identify the correct elements using clues such as numbers of protons,locations (family/period), number of neutrons, n

umbers of electrons
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0

an element's name, chemical symbol, atomic number, atomic mass.

IDK what you are even asking for

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I 13 Suggest why this group is called Group 8.​
yarga [219]

Answer:

because it's in group 8

Explanation:

3 0
3 years ago
in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0
3 years ago
The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi
Klio2033 [76]

We know that when calculating percent yield, we use the equation:


Percent yield=\frac{Actual yield (A)}{Theoretical yield (T)}


Since the quantities that we are given in the question are equal, we can just directly divide them to find percent yield:


Percentyield=\frac{480kg}{550kg} =0.8727*100=87.27


So now we know that the percent yield of the synthesis is 87.27%.

7 0
3 years ago
What is the symbol for temperature?<br><br> m<br><br> q<br><br> T<br><br> J
Tcecarenko [31]

Answer:

T

Explanation:

m is mass

q is heat

J is energy

6 0
2 years ago
2. The Density of Water is 1.0000g/cm3. Based on this property of water,
Vanyuwa [196]

Answer:

if the object sank then that object has a greater density then water. if the object floated then its density is lower then water.

Explanation:

lets say object 1 has a density of 24/cm3. the density is greater then water (1.0000g/cm3) so it would sink. now lets say object 2 has a density of 0.79383g/cm3 since it's less then the density of water (1.0000g/cm3) it would float.

7 0
3 years ago
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