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ZanzabumX [31]
3 years ago
11

How many grams are there in 11.8 moles of sodium hydroxide

Chemistry
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

16

Explanation:

the number a grams is 16

natita [175]3 years ago
3 0

Answer:

Roughly 471.96589800000004. Hope i helped :D

Explanation:

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How is salt obtained or manufactrured​
Novay_Z [31]

Answer:

There are three methods used to produce salt: solar, evaporation and rock mining.

Explanation:

7 0
3 years ago
Place the following compounds in order of increasing vapor pressure. methane, CH4; pentane, CH3CH2CH2CH2CH3; 1-propanol, CH3CH2C
ella [17]

Explanation:

A compound that contains more stronger bonds will need more amount of heat in order to break the bonds so that it changes into vapor state.

In 1-propanol, there is hydrogen bonding and it is stronger in nature. As a result, more amount of heat is required to break the bonds between molecules of 1-propanol.

Whereas in propanone, there will be dipole-dipole interactions which are less stronger than hydrogen bonding. Hence, propanone molecule will need less amount of energy than 1-propanol.

On the other hand, pentane will need more amount of heat as it has longer chain of carbon atoms as compared to methane.

Thus, we can conclude that given compounds are arranged in order of increasing vapor pressure as follows.

         methane < pentane < propanone < 1-propanol

5 0
3 years ago
Read 2 more answers
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the r
QveST [7]
The reaction is combination of hydrogen molecules and oxygen molecules and form water. So the oxygen and hydrogen required together is equal to the mass of the water formed.
5 0
4 years ago
when 1.570 grams of the compound is vaporizedar 300 degrees celius and 1 atmosphere, the gas occupies a volume of 577 milliliter
Archy [21]

Answer:

128 g/mol

Explanation:

The molar mass is how much a mol of the substance weight.

In this question the weight is given (1.570 g).

To find the number of moles in the sample, we use the ideal gas law: PV=RnT

P= 1atm

V= 577mL= 0.577L

R (universal gas constant)= 0.08206(\frac{atm*L}{mol*K})

n= number of moles

T= 300°C= 573.15K

Solving for n:

n= \frac{1 atm*0.577L}{0.08206\frac{atm*L}{mol*K}*573.15} <em>k</em>

n=0.0123mol

Molar mass=\frac{1.570g}{0.0123 mol}

Molar mass=128\frac{g}{mol}

7 0
3 years ago
Read 2 more answers
4. How many minutes are there in 1.000 week?<br> please help
ioda
There are 10,080 minutes
5 0
3 years ago
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