Answer:
The rate of disappearance of C₂H₆O = 2.46 mol/min
Explanation:
The equation of the reaction is given below:
2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O
From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.
The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus, the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.
Rate of disappearance of C₂H₆O = 1.64 mol/min of Cr₂(SO₄)₃ * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃
Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O
Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min
In the complete combustion of 1.60 moles of benzene, C6H6, 12 moles of oxygen, O2, is consumed.
Combustion is defined as the process of burning something. In chemistry, combustion refers to the chemical process between a fuel and an oxidant, usually oxygen to produce heat and light in the form of flame.
In a complete combustion, oxygen is sufficient to react with any hydrocarbons to produce carbon dioxide and water.
Balancing the combustion reaction of benzene, we have:
2C6H6 + 15 O2 = 12CO2 + 6H2O
Based on the balanced combustion reaction above, 2 moles of benzene requires 15 moles of oxygen to have a complete combustion.
If we have 1.60 moles C6H6,
moles O2 = mole ratio x mole of benzene
moles O2 = (15 moles O2/2 moles C6H6) x 1.60 moles C6H6
moles O2 = 12
To learn more about combustion: brainly.com/question/9913173
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The answer to your question is B
Because of the characteristic of catalyst. The catalyst is used to accelerate the reaction rate and will not participate the reaction itself. The catalyst can not be changed or consumed during the reaction. So it does not need to be replaced.
