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AleksandrR [38]
2 years ago
13

Which two values are located at the same point on a number line? 1/2 and 2 , 2/2 2 , 2/1 2 , 2/1 and 1

Mathematics
1 answer:
grandymaker [24]2 years ago
8 0

Answer:  \frac{2}{2},1\ \text{and}\ \frac{2}{2},1

Step-by-step explanation:

\Rightarrow \dfrac{2}{2}\ \text{is equivalent to 1}

\text{So, }\ \dfrac{2}{2},2\ \text{is equivalent to 1,2}

\text{Similarly, }\ \dfrac{2}{1},1\ \text{represents 2,1 or 1,2}

\text{So,}\ \frac{2}{2},1\ \text{and}\ \frac{2}{2},1\ \text{are represents same on number line.}

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Sir John Franklin was an explorer who traveled in Canada and the United States he was 33 years old when he began exploring North
Dmitry_Shevchenko [17]
He was 51 years old. He was 33 when he first started exploring. Then 17 years later he explored again so you add 17 +33 =50 . Then 11 years later he died so you add 11 to 50 =51
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3 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
Finger [1]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

7 0
2 years ago
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The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea
Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

N(A\text{ or B)=N(A)+N(B)-N(A and B)}

N (professors)

\begin{gathered} =6+9 \\ =15 \end{gathered}

N(Male)

\begin{gathered} =6+5 \\ =11 \end{gathered}

N(professors and male)

=6

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}

N(People to choose from)

\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}

Then probablitiy is:

\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}

Then the probability is 10/13

6 0
11 months ago
Simplify.<br><br>1 – 2u + u + 4​
liq [111]

Answer:

-u+5

Step-by-step explanation:

plz mark as brainliest

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3 years ago
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Answer:

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Step-by-step explanation:

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