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My name is Ann [436]
3 years ago
8

Congruent Figures

Mathematics
1 answer:
snow_lady [41]3 years ago
5 0
It’s b becuase I just took the test on edge 2020 so just trust me I swear
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Each leg of a 45-45-90 triangle has a length of 6 units. What is the length of its hypotenuse?
andreyandreev [35.5K]
Use the Pythagorean theorem:
(\hbox{one leg})^2+(\hbox{the other leg})^2=(\hbox{hypotenuse})^2 \\
6^2+6^2=x^2 \\
6^2 \times 2=x^2 \\
\sqrt{6^2 \times 2}=x \\ \sqrt{6^2} \times \sqrt{2}=x \\ 6\sqrt{2}=x

 
The length of the hypotenuse is 6√2 units.
5 0
3 years ago
Vanessa draws one side of equilateral ΔABC on the coordinate plane at points A(–2, 1) and B(4,1). What are the possible coordina
sukhopar [10]

Answer:

Possible C:

(1 , 1 + 3sqrt(3))

(1 , 1 - 3sqrt(3))

Step-by-step explanation:

AB = 6 units

Midpoint of AB is (1,1)

C would be at x = 1

So, (1,y)

(y-1)² + (1+2)² = 6²

(y-1)² = 36 - 9

(y-1)² = 27

y - 1 = 3sqrt(3)

y - 1 = -3sqrt(3)

y = 1 + 3sqrt(3)

y = 1 - 3sqrt(3)

7 0
4 years ago
A production manager randomly sampled production lines at a factory that produces automobiles. She wanted to find out how many p
Elena-2011 [213]

Answer:

The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).

Step-by-step explanation:

A confidence interval for a population proportion is a function of the sample proportion and the margin of error.

The interval has two bounds, a lower bound and an upper bound.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this problem, we have that:

Sample proportion 0.08

Margin of error 0.01

0.08 - 0.01 = 0.07

0.08 + 0.01 = 0.09

The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).

5 0
3 years ago
On your last credit card statement, you had a previous balance of $98.14, payments of $10, a periodic rate of 1.34 percent, and
a_sh-v [17]
New balance
98.14−10+(88.14×(0.0134÷12)+34.89
=123.13 .....answer
8 0
3 years ago
Read 2 more answers
What is the equation in vertex form of a parabola with vertex (-2, -2) that opens downward and is stretched by a factor of 5?
Galina-37 [17]

Answer:

D).  -5(x + 2)^2 - 2.

Step-by-step explanation:

Parabola which Opens down and vertex (-2, -2) is :

f(x) = a(x + 2)^2 - 2 where a is negative

Stretch by factor 5 gives:

-5(x + 2)^2 - 2.

5 0
3 years ago
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