There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.
Ima do the algebra way:
SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >
4-6x=2-6x.
Now solve. And get > 0 aka Infinite Solution.
Answer:
A. Right angle -- if you multiply the slopes of 2 intersecting lines and you "-1" then the lines are perpendicular - in this case the line in quadrant 3 has a slope of "1" and the line in quadrant 4 has a slope of "-1", hence their product is "-1" and the angles formed at the intersection of the lines are right angles.
Step-by-step explanation:
Answer:
Option C: 41
Step-by-step explanation:
<ABD+<CBD=90
<ABD=8x+1
<CBD=6x+5
(8x+1)+(6x+5)=90
Combine like terms
(8x+6x)+(1+5)=90
14x+6=90
14x=90-6
14x=84
divide both sides by 14
x=6
Now we plug that value into <DBC = 6x+5
6(6)+5=
36+5
41
Answer:
The number of hamburgers is 109.
Step-by-step explanation:
Let h = number of hamburgers
Let c = number of cheeseburgers
The total number sold gives us the equation below.
h + c = 327
"The number of cheeseburgers sold was two times the number of hamburgers sold.
This gives us the equation
c = 2h
Now we substitute c with 2h in the first equation and solve for h.
h + 2h = 327
3h = 327
h = 109
The number of hamburgers is 109.
Answer:
There are 2^3 = 8 possible outcomes after tossing a fair coin fairly 3 times. The 8 possible outcomes are: TTT, HTT, THT, TTH, HHT, HTH, THH, HHH. Exactly 2 of 8 possible outcomes result in 3 of the same faces showing up.
Step-by-step explanation:
