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riadik2000 [5.3K]
3 years ago
5

What is a trinomial?

Mathematics
2 answers:
marin [14]3 years ago
7 0

A trinomial is a polynomial with three terms.

For example, a²b - 3ab + 2b or x² - 5x + 6.

V125BC [204]3 years ago
6 0

Answer:

In elementary algebra, a trinomial is a polynomial consisting of three terms or monomials.

The definition of a trinomial is a math equation that has three terms that are connected by plus or minus notations. An example of a trinomial is 6x squared + 3x + 5.

A polynomial with three terms is called a trinomial. Trinomials often (but not always!) have the form x2 + bx + c.

Step-by-step explanation:

ummm hope this helps... (o^-’)b

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horrorfan [7]

Answer:

B

Step-by-step explanation:

180-118=42 so angle c=42

add 42 +76 =138

in a triangle all degrees ad up to 180 so

subtract 138 from 180=42

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In this case just do it left to right, as multiplication comes before addition/subtraction. So 7x3x2+5-3=21x2+5-3=42+5-3=47-3=44=k.
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leva [86]

6y-4=4y+2

2y=6, so y=3.

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This is an isosceles triangle.


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3 years ago
What is the value of the following expression when p=4?<br><br> 4p+9
Gelneren [198K]

Answer:

4p+9=

(first start with multiple or division division from right to left then with addition from right to left)

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3 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
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