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Ostrovityanka [42]

2 years ago

5

Atoms and molecules are constantly in motion. The more energy the atom or molecule contains, the faster they move about. In whic

h state of matter do the atoms and molecules have the least energy

1 answer:

Rus_ich [418]2 years ago

5 0

Answer:

Solid

Explanation:

You might be interested in

Intermolecular forces are the interactions between molecules and are generally weaker than bonds within molecules. Which molecul

telo118 [61]

Answer:

Molecules that will have dipole-dipole forces with like molecules include the water (H2O) molecule. Another example is the Hydrogen Chloride (HCl) molecule.

Explanation:

Intermolecular forces are forces of attraction or repulsion that exist between particles (ions, atoms, or molecules) that are close/in nearby proximity to each other. Usually, intermolecular forces are not as strong as intramolecular forces which create covalent or ionic bonds between the atoms that exist within molecules. Dipole-dipole interactions occur whenever the partial charges that exist within one molecule are attracted to the opposite partial charges that exist within another different molecule that is nearby and similar in composition: the positive end/charges of one molecule are attracted to the negative end/charges of another similar molecule.

An example of molecules that exhibit dipole-dipole interaction is the water (H2O) molecule. Another molecule which exhibits dipole–dipole interaction is the Hydrogen Chloride (HCl) molecule, whereby the positive end of one HCl molecule usually attracts the negative end of another HCl molecule.

6 0

3 years ago

7. Use the concepts of relative abundance and relative weight to explain why carbon has an atomic mass of 12.011 amu when there

Dvinal [7]

The uncertainties of the delta measurements and the uncertainty of the atomic weight derivedfrom the best measurement of isotopic abundances constrain the number of significant figures in theatomic-weight values of the upper and lower bounds. For carbon, the fifth digit after the decimal pointis uncertain because of the uncertainty value of 0.000 027. Therefore, the number of significant digitsin the atomic-weight value is reduced to four figures after the decimal point. The Commission may rec-ommend additional conservatism and reduce the number of significant figures further. For the lowerbound of carbon, 12.009 635 is truncated to 12.0096. For an upper bound, the trailing digit is increasedto ensure the atomic-weight interval encompasses the atomic-weight values of all normal materials. Inthe case of carbon, the upper bound is adjusted from 12.011 532 to 12.0116 to express four digits afterthe decimal point. The lower and upper bounds are evaluated so that the number of significant digits ineach is identical. If a value ends with a zero, it may need to be included in the value to express therequired number of digits. The following are examples of lower and upper atomic-weight bounds foroxygen that could be published by the Commission in its various tables.

---------------------------

Extracted from" Atomic weights of the elements 2009 (IUPAC Technical Report)"

5 0

3 years ago

Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4

krok68 [10]

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

6 0

3 years ago

Please help with this

dlinn [17]

Answer:

A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is 0.67 atm.

Step by Step Explanation?

Boyle's law states that in constant temperature the variation volume of gas is inversely proportional to the applied pressure.

The formula is,

P₁ x V₁ = P₂ × V₂

Where,

P₁ is initial pressure = 1 atm

P2 is final pressure = ? (Not Known)

V₁ is initial volume = 10 L

V₂ is final volume = 15 L

Now put the values in the formula,

\begin{gathered}\rm 1\times 10 = P_2\times 15\\\\\rm P_2 = \frac{10}{15\\} \\\\\rm P_2 = 0.67\end{gathered]

Therefore, the answer is 0.67 atm.

5 0

2 years ago

Read 2 more answers

A truck traveled at a constant speed for 6 hours. Then, it

gavmur [86]

Answer:

2.4 hrs

Explanation:

The constant speed of the truck for 6 hrs can be calculated by: speed=distance/time. Speed =(876-228)/6=648/6=108m/s. So the decreased speed = (108-13)=95m/h. Now, speed =distance /time We get 95m/h = 228/t. t=228/95 hrs = 2.4 hrs PLEASE MARK ME THE BRAINLIEST!!

7 0

3 years ago

Read 2 more answers