One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh
2 answers:
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Answer : The concentration of and
at equilibrium is, 0.0158 M and 0.00302 M respectively.
Explanation :
First we have to calculate the concentration of
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 0.0163 0.00415 0.00276
At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)
As we are given:
Concentration of at equilibrium = 0.00467 M
That means,
(0.00415+x) = 0.00467
x = 0.00026 M
Concentration of at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M
Concentration of at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M
Answer:
time taken for one-half of the BrO⁻ ion to react is t= 27.45 secs
Explanation:
equation of reaction
3BrO⁻(aq) → BrO₃⁻(aq) + 2Br⁻(aq) (second order reaction)
given
the slope of the graph is 0.056M⁻¹s⁻¹ = k(constant)
initial concentration [A]₀ = 0.65M
for second order reaction,we can calculate the time taken for one-half of the BrO- ion to react using:
=
₀ ⁺ k × t
where initial concentration [A]₀ = 0.65M
[A] = [A]₀÷2 = 0.325M
=
+ 0.056M⁻¹s⁻¹ × t
3.077= 1.54 + 0.056t
3.077-1.54=0.056t
1.537=0.056t
t= 27.45 secs