Answer:
The formal thinker would take a systematic approach in the combination of the liquids, thereby eliminating several unnecessary combinations that the concrete thinker would definitely combine.
Explanation:
The formal operational stage in thinking begins when a child gets to the age of 12 and continues to adulthood. The formal operational stage provides an individual with the ability to think abstractly by manipulating ideas in their head without concretely manipulating it. A concrete would have to see something to be able to manipulate any ideas.
Answer:
Do you think that the mole should be considered a base unit in the SI system?
The mole is not a base unit on a par with the six property base units; it cannot be used in significant physical–chemical comparisons until the subscript parameter p in mole-of-Ep has been given a certain “value”."
Explanation:
Answer:
D. the conversion of one element into another
Explanation:
Transmutation is the action of changing or the state of being changed into another form. Therefore, D is the correct answer choice.
Answer:
[KOH] = 7.76×10⁻³ M
[Ca(OH)₂] = 2.39×10⁻³ M
Explanation:
KOH → K⁺ + OH⁻
pH = - log [H⁺]
14 = pH + pOH
pOH = - log [OH⁻]
10^-pOH = [OH⁻]
14 - 11.89 = 2.11 → pOH
2.11 = - log [OH⁻]
10⁻²°¹¹ = [OH⁻] → 7.76×10⁻³ M
As ratio is 1:1, [KOH] = 7.76×10⁻³ M
14 - 11.68 = 2.32 → pOH
10⁻²°³² = [OH⁻] → 4.78×10⁻³ M
Ca(OH)₂ → Ca²⁺ + 2OH⁻
Ratio is 2:1, so I will have the half of base.
4.78×10⁻³ /2 = 2.39×10⁻³ M
For the whole set of problems, always remember the Avogadro’s
number is 6.023*10^23 units per mole of a substance. Units could be atoms,
molecules or formula units.
The first question asks for the number of molecules of NaNO3.
The molar mass of NaNO3 is 85 grams per mole. So,
<span>150g NaNO3(1mole NaNO3/85 grams NaNO3)(6.023*10^23
molecules/1mole NaNO3)=1.063*10^24 molecules of NaNO3</span>
<span>5.7*10^46 molecules of NaNO3(1mole NaNO3/6.023*10^23
molecules)(85 grams NaNO3/1mole NaNO3) = 8.044*10^24 grams NaNO3</span>
For the molar mass of water, we have 18.02grams per mole.
301 moles H2O(18.02 grams H2O/1
mole H2O) = 5424.02 grams H2O
For the molar mass of sulfuric
acid, we have 98.08 grams per mole.
25g H2SO4(I mole H2SO4/98.08g H2SO4) =
0.2549 mole H2SO4
For the molar mass of Ca(OH)2,
we have 74.1 grams per mole.
252gCa(OH)2(1mol/74.1g)(6.023*10^23/1mol)
= 2.048*10^24 molecules of Ca(OH)2
For the molar mass of calcium,
we have 40 grams of Ca per mole.
6.7*10^35 atoms Ca(1 mole
Ca/6.023*10^23 atoms)(40g Ca/1mol Ca) = <span>4.45*10^13 grams Ca</span>