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3 years ago

The gram-formula mass of NO2 is defined as the mass of

2 answers:

4 0

The correct answer is (1) one mole of NO2.

The gram formula mass is also known as the molar mass and is defined by the mass over one mole of a substance.

Hope this helps~

Alika [10]3 years ago

3 0

Correct answer is 1 - one mole of NO2 .

Gram formula mass can be defined as the mass of 1 mole (6.022 x 10²³ particles) of compound in grams. This is similar to molar mass. Gram formula mass is also calculated by adding the total mass of each element present in the given formula.

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Help plz:)))I’ll mark u Brainliest

Triss [41]

Answer:

Explanation:

We want the energy required for the transition:

CO 2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1 to get an answer in Joules as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

6 0

3 years ago

An excess of sodium carbonate, Na, CO3, in solution is added to a solution containing 17.87 g CaCl2. After performing the

Brrunno [24]

Answer:

Approximately $81.84\%$ .

Explanation:

Balanced equation for this reaction:

${\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)$ .

Look up the relative atomic mass of elements in the limiting reactant, $\rm CaCl_{2}$ , as well as those in the product of interest, $\rm CaCO_{3}$ :

$\rm Ca$ : $40.078$ .
$\rm Cl$ : $35.45$ .
$\rm C$ : $12.011$ .
$\rm O$ : $15.999$ .

Calculate the formula mass for both the limiting reactant and the product of interest:

$\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}$ .

$\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the quantity of the limiting reactant ( $\rm CaCl_{2}$ ) available to this reaction:

$\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}$ .

Refer to the balanced equation for this reaction. The coefficients of the limiting reactant ( $\rm CaCl_{2}$ ) and the product ( ${\rm CaCO_{3}}$ ) are both $1$ . Thus:

$\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1$ .

In other words, for every $1\; \rm mol$ of $\rm CaCl_{2}$ formula units that are consumed, $1\; \rm mol\!$ of $\rm CaCO_{3}$ formula units would (in theory) be produced. Thus, calculate the theoretical yield of $\rm CaCO_{3}\!$ in this experiment:

$\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}$ .

Calculate the theoretical yield of this experiment in terms of the mass of $\rm CaCO_{3}$ expected to be produced:

$\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}$ .

Given that the actual yield in this question (in terms of the mass of $\rm CaCO_{3}$ ) is $13.19\; \rm g$ , calculate the percentage yield of this experiment:

$\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}$ .

6 0

3 years ago

The addition of perchloric acid to pure water causes the conductivity to _________.

Olin [163]

Adding perchloric acid to water would cause it's conductivity to increase.

3 0

3 years ago

Read 2 more answers

How does a phospholipid behave in water?

bonufazy [111]

It is A since the tails are hydrophobic.

5 0

3 years ago

Read 2 more answers

A wildfire can destroy thousands of acres of forest. Explain two positive effects and two negative effects that a wildfire can h

Lynna [10]

Explanation:

Wildfires destroy forests that are great carbon sinks. This means that large amount of carbon dioxide are released back into the atmosphere. Carbon dioxide is a greenhouse gas and this will contribute to global warming.

An advantage is that the wildfire will spur secondary ecological succession. This kind of succession improves the biodiversity of the forest. Biodiversity improves the productivity of the ecosystem.

Learn More:

For more on secondary ecological succession check out;

brainly.com/question/2456852

brainly.com/question/13866761

#LearnWithBrainly

5 0

3 years ago